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Lubov Fominskaja [6]
3 years ago
11

If the speed of sound in air is 343 m/s and the wavelength of this note is 2.62 m, what is the frequency of this C3 note? (Round

your answer to three significant figures.)
Physics
1 answer:
snow_lady [41]3 years ago
8 0

Answer:

<em>The frequency of of the note = 131 Hz.</em>

Explanation:

<em>Frequency:</em><em> Frequency can be defined as the number of complete oscillation completed by a wave in one seconds. The S.I unit of frequency is Hertz ( Hz)</em>

v = λf ............................ Equation 1

Making f the subject of the equation,

f = v/λ .......................... Equation 2

Where v = Speed, λ = wavelength, f = frequency

<em>Given: v = 343 m/s, λ = 2.62 m.</em>

<em>Substituting these values into equation 2</em>

<em>f = 343/2.62</em>

<em>f = 131 Hz</em>

<em>Thus the frequency of of the note = 131 Hz.</em>

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How does the strong nuclear force hold the nucleus of an atom together?
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What is the half-reaction that occurs at the cathode during the electrolysis of molten potassium bromide?
polet [3.4K]

The complete ionization of KBr into its constituents is:<span>
<span>KBr (s)  --->  K+ (aq)  +  Br- (aq)</span></span>

<span>
During electrolysis, oxidation takes place at the anode electrode. This means that an ion is stripped off its electron hence becoming more positive:
<span>2 Br- (aq)  --->  Br2 (g) + 2e- </span></span>

We can see that Bromine gas Br2 is evolved at the anode. 

<span>
<span>Meanwhile at the cathode, the reduction reaction occurs. Which means that the electron from the anode electrode is used to make an ion more negative:
<span>2K+ (aq)  +  2e-  --->  2K (s) </span></span>
Hence, through reduction, solid potassium is deposited on the plate.</span>

 

 

Half reactions:

<span>Anode: 2 Br- (aq)  --->  Br2 (g) + 2e- </span>                       

<span>Cathode: 2K+ (aq)  +  2e-  --->  2K (s) </span>

7 0
3 years ago
A car starts from rest, speeds up with constant acceleration, and travels 400 meters in 10 seconds. What was the acceleration of
PIT_PIT [208]

Answer:

Acceleration of the car will be a=8m/sec^2

Explanation:

We have given that car starts from rest so initial velocity of the car u = 0 m/sec

And car traveled 400 m in 10 sec

So distance traveled by car s = 400 m

Time taken to compete this distance t = 10 sec

We have to find the acceleration of the car

From second equation of motion we know that s=ut+\frac{1}{2}at^2

So 400=0\times 10+\frac{1}{2}\times a\times 10^2

a=8m/sec^2

So acceleration of the car will be a=8m/sec^2

7 0
3 years ago
The freezer compartment in a conventional refrigerator can be modeled as a rectangular cavity 0.3 m high and 0.25 m wide with a
Mkey [24]

Answer:

Thickness of Styrofoam insulation is 0.02741 m.

Explanation:

Given that,

Height = 0.25 m

Depth = 0.5 m

Power = 400 W

Temperature = 33°C

We need to calculate the area of Styrofoam

Using formula of area

A=2(lb+bh+hl)

Put the value into the formula

A=2(0.3\times0.5+0.25\times0.5+0.5\times0.3)

A=0.85\ m^2

Inner surface temperature of freezer

T_{i}=-10°C=263\ K

Outer surface temperature of freezer

T_{o}=33+273=306\ K

We need to calculate the thickness of Styrofoam insulation

Using Fourier law,

q=\dfrac{kA}{L}(T_{o}-T_{i})

L=\dfrac{kA}{q}(T_{o}-T_{i})

Put the value into the formula

L=\dfrac{0.30\times0.85}{400}(306-263)

L=0.02741\ m

Hence, Thickness of Styrofoam insulation is 0.02741 m.

3 0
3 years ago
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