If the speed of sound in air is 343 m/s and the wavelength of this note is 2.62 m, what is the frequency of this C3 note? (Round
1 answer:
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The height of the building is 53.4 m (projectile motion)
Explanation:
The motion of the ball is a projectile motion, so it follows a parabolic path which consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction
First of all, we consider the horizontal motion, which is a uniform motion at constant speed. The equation that gives the horizontal distance travelled is:
where:
is the horizontal velocity of the ball, which is constant since there are no forces in this direction
d = 165 m is the horizontal distance travelled by the ball
Solving for t, we find the time of flight:
Now we analyze the vertical motion: it is an accelerated motion, we can use the suvat equation
where
s is the vertical displacement, which is the height of the building
u = 0 is the initial vertical velocity of the ball
t = 3.3 s is the time of flight
is the acceleration of gravity
Solving for s, we find the height of the building:
Learn more about projectile motion here:
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