Answer:
0.2885 m/s²
Explanation:
The formula for centripetal acceleration is given as;
![a_c=v^2/r](https://tex.z-dn.net/?f=a_c%3Dv%5E2%2Fr)
Given that;
speed = v = 1.5m/s
radius = r = 7.8
![a_c=v^2/r\\\\\\a_c=1.5^2/7.8\\\\\\a_c=0.2885m/s^{2}](https://tex.z-dn.net/?f=a_c%3Dv%5E2%2Fr%5C%5C%5C%5C%5C%5Ca_c%3D1.5%5E2%2F7.8%5C%5C%5C%5C%5C%5Ca_c%3D0.2885m%2Fs%5E%7B2%7D)
When a pendulum is at the midpoint of its oscillation, hanging straight down ...
-- that's the fastest it's going to swing, so its kinetic energy is maximum;
and
-- that's the lowest it's going to get, so its potential energy is minimum.
'c' is your choice.
Answer:
Both of them.
Explanation:
They are both because when your analyzing data , that is what happen's.
Answer:
C. 2 and 4
Explanation:
my teacher went over it and the answer was that
Answer:
Explanation:
In the first case you can use the expression for the Doppler effect when the source is getting closer and getting away
( 1 )
( 2 )
f' = perceived frequency when the source is getting closer
f'' = perceived frequency when the source is getting away
f = source frequency
v = relative speed
vs = sound speed
by dividing (1) and (2) you have
![\frac{f'}{f''}=\frac{f}{f}\frac{\frac{v}{v-v_s}}{\frac{v}{v+v_s}}=\frac{v+v_s}{v-v_s}\\\\f'v-f'v_s=f''v+f''v_s\\\\v(f'-f'')=v_s(f''+f')\\\\v=v_s\frac{f''+f'}{f'-f''}=(340\frac{m}{s})\frac{1370Hz+1330Hz}{1370Hz-1330Hz}=67.5\frac{m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bf%27%7D%7Bf%27%27%7D%3D%5Cfrac%7Bf%7D%7Bf%7D%5Cfrac%7B%5Cfrac%7Bv%7D%7Bv-v_s%7D%7D%7B%5Cfrac%7Bv%7D%7Bv%2Bv_s%7D%7D%3D%5Cfrac%7Bv%2Bv_s%7D%7Bv-v_s%7D%5C%5C%5C%5Cf%27v-f%27v_s%3Df%27%27v%2Bf%27%27v_s%5C%5C%5C%5Cv%28f%27-f%27%27%29%3Dv_s%28f%27%27%2Bf%27%29%5C%5C%5C%5Cv%3Dv_s%5Cfrac%7Bf%27%27%2Bf%27%7D%7Bf%27-f%27%27%7D%3D%28340%5Cfrac%7Bm%7D%7Bs%7D%29%5Cfrac%7B1370Hz%2B1330Hz%7D%7B1370Hz-1330Hz%7D%3D67.5%5Cfrac%7Bm%7D%7Bs%7D)
but this is the relative velocity, you have that
![v=v_{sir}-v_{car}\\v_{sir}=v+v_{car}=67.5\frac{m}{s}+35\frac{m}{s}=102.5\frac{m}{s}](https://tex.z-dn.net/?f=v%3Dv_%7Bsir%7D-v_%7Bcar%7D%5C%5Cv_%7Bsir%7D%3Dv%2Bv_%7Bcar%7D%3D67.5%5Cfrac%7Bm%7D%7Bs%7D%2B35%5Cfrac%7Bm%7D%7Bs%7D%3D102.5%5Cfrac%7Bm%7D%7Bs%7D)
a. hence, the speed of the police car is 102.5m/s