At a point on the streamline, Bernoulli's equation is
p/ρ + v²/(2g) = constant
where
p = pressure
v = velocity
ρ = density of air, 0.075 lb/ft³ (standard conditions)
g = 32 ft/s²
Point 1:
p₁ = 2.0 lb/in² = 2*144 = 288 lb/ft²
v₁ = 150 ft/s
Point 2 (stagnation):
At the stagnation point, the velocity is zero.
The density remains constant.
Let p₂ = pressure at the stagnation point.
Then,
p₂ = ρ(p₁/ρ + v₁²/(2g))
p₂ = (288 lb/ft²) + [(0.075 lb/ft³)*(150 ft/s)²]/[2*(32 ft/s²)
= 314.37 lb/ft²
= 314.37/144 = 2.18 lb/in²
Answer: 2.2 psi
(a) 3000 V
For two parallel conducting plates, the potential difference between the plates is given by:
![\Delta V=Ed](https://tex.z-dn.net/?f=%5CDelta%20V%3DEd)
where
E is the magnitude of the electric field
d is the separation between the plates
Here we have:
is the electric field
d = 4.00 cm = 0.04 m is the distance between the plates
Substituting,
![\Delta V=(7.50\cdot 10^4 V/m)(0.04 m)=3000 V](https://tex.z-dn.net/?f=%5CDelta%20V%3D%287.50%5Ccdot%2010%5E4%20V%2Fm%29%280.04%20m%29%3D3000%20V)
(b) 750 V
The potential difference between the two plates A and B is
![\Delta V = V_B - V_A = 3000 V](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20V_B%20-%20V_A%20%3D%203000%20V)
Let's take plate A as the plate at 0 volts:
![V_A = 0 V](https://tex.z-dn.net/?f=V_A%20%3D%200%20V)
The potential increases linearly going from plate A (0 V) to plate B (3000 V).
So, if the potential difference between A and B, separated by 4 cm, is 3000 V, then the potential difference between A and a point located at 1 cm from A is given by the proportion:
![3000 V : 4 cm = V(1 cm) : 1 cm](https://tex.z-dn.net/?f=3000%20V%20%3A%204%20cm%20%3D%20V%281%20cm%29%20%3A%201%20cm)
and solving for V(1 cm) we find:
![V(1 cm)=\frac{(3000 V)(1 cm)}{4 cm}=750 V](https://tex.z-dn.net/?f=V%281%20cm%29%3D%5Cfrac%7B%283000%20V%29%281%20cm%29%7D%7B4%20cm%7D%3D750%20V)
Answer:
The supersonic jet has a greater acceleration
The eagle momentum : 320 kg.m/s
<h3>Further explanation</h3>
Given
mass = 32 kg
d = 100 m
t = 10 s
Required
The momentum
Solution
The velocity of the eagle :
![\tt v=\dfrac{d}{t}\\\\v=\dfrac{100}{10}=10~m/s](https://tex.z-dn.net/?f=%5Ctt%20v%3D%5Cdfrac%7Bd%7D%7Bt%7D%5C%5C%5C%5Cv%3D%5Cdfrac%7B100%7D%7B10%7D%3D10~m%2Fs)
The momentum (P) :
![\tt P=m\times v\\\\P=32\times 10\\\\P=320~kg.m/s](https://tex.z-dn.net/?f=%5Ctt%20P%3Dm%5Ctimes%20v%5C%5C%5C%5CP%3D32%5Ctimes%2010%5C%5C%5C%5CP%3D320~kg.m%2Fs)
Properties and characteristics of the organism(mostly eukaryotes )determin e the kingdom