Answer:
0.00325 moles/liter/second
Explanation:
The tangent line has a slope of (y2 -y1)/(x2 -x1) = (0.35-0.48)/(40-0) = -0.00325.
The rate of the reaction is about 0.00325 moles/liter/second.
_____
This is the rate of decrease of the concentration of A.
Answer:
t = 3.88 seconds
Explanation:
Given that,
A ball is thrown horizontally from the top of a 73.9-m building and lands 183 m from the base of the building.
We need to find the time for which the ball is in air. Let the time be t.

Here, a = -g,
and y = 0
u is initial velocity, u = 0

So, the ball is in the air for 3.88 seconds.
Answer:
42.6 N/m
Explanation:
The spring constant can be found by using Hooke's law:
F = kx
where
F is the force applied
k is the spring constant
x is the stretching/compression of the spring
In this problem, the mass applied is
m = 0.10 kg
so the force applied is the weight of the mass:

The stretching of the spring is
x = 2.3 cm = 0.023 m
So the spring constant is

Answer:
v = 112.424 km / s
Explanation:
Given:
d = 3.84 x 10 ⁸ m , R = 63 x 10³ m , m earth = 5.97 x 10²⁴ kg , G = 6.67 x 10⁻¹¹ N * m² / kg² , v₁ = 14.8 x 10 ³ m / s
Using the equation
KE + PE = initial KE + PE
¹/₂ * m * v₂² - G * m/ R = ¹/₂ * m * v₁² - G * m/(R+d)
v₂² = v₁² + 2*G * m [ 1/R - 1/(R+d) ]
v₂² = 14.8 x 10 ³ m /s + 2 * 6.67 x 10⁻¹¹ N * m² / kg² * 5.97 x 10²⁴ kg [ 1 / 63 x 10³m - 1 / ( 63 x 10³ + 3.84 x 10⁸ m ) ]
v = √ 1.26 x 10¹⁰ m² / s²
v = 112.424 x 10³ m/s
v = 112.424 km / s