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lyudmila [28]
3 years ago
7

A 52.0-kg sandbag falls off a rooftop that is 22.0 m above the ground. The collision between the sandbag and the ground lasts fo

r a total of 17.0 ms. What is the magnitude of the average force exerted on the sandbag by the ground during the collision?
Physics
1 answer:
sergiy2304 [10]3 years ago
4 0

Answer:

F = 7,916,955.0N

Explanation:

According to newtons second law

Force = mass * acceleration

Given

mass = 52.0kg

distance S = 22.0m

time t = 17.0 ms = 0.017s

We need to get the acceleration first using the formula;

S = ut+ 1/2at²

22 = 0 + 1/2 a(0.017²)

22 = 0.0001445a

a = 22/0.0001445

a = 152,249.13m/s²

The magnitude of the average force exerted will be;

F = ma

F = 52 * 152,249.13

F = 7,916,955.0N

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Is it possible for a system to have negative potentialenergy?
sineoko [7]

Answer:

Yes, since the choice of the zero o potential energy is arbitrary.

Explanation:

The kinetic energy is due to the motion of the object. The expression for the kinetic energy is as follows;

KE=\frac{1}{2}mv^{2}

Here, m is the mass of the object and v is the velocity of the object.

The kinetic energy can not be negative as the velocity is squared. It can be zero and positive.

Potential energy: It is the energy is due to the position of the object.

The expression for the potential energy is as follows;

PE= mgh

Here, g is the acceleration due to gravity and height.

Height can be taken from the reference point, zero which can be taken below zero and above zero. Zero is taken as origin. Below zero, the height is taken as negative and above zero, the height is taken as positive.

The potential energy can be zero, positive and negative.

The total energy is the sum of kinetic energy and potential energy.

E= KE + PE

Here, KE is the kinetic energy and PE is the potential energy.

Therefore, the option (B) is correct.

5 0
2 years ago
An object is at rest on the ground. The object experiences a downward gravitational force from Earth. Which of the following pre
Montano1993 [528]

Answer:

A) and B) are correct.

Explanation:

If the object is at rest, it means that no net force is exerted on it.

As the object experiences a downward gravitational force from Earth, in order to be at rest, it must experience an upward force with the same magnitude as the gravitational force on the object.

This force is supplied by the normal force, which can adopt any value in order to meet the condition imposed by Newton´s 2nd Law, and is always perpendicular to the surface on which the object is placed (in this case, the ground).

At a molecular level, this normal force is supplied by the bonded molecules of the ground that behave like small springs being compressed by the molecules of the object, exerting an upward restoring force upward on them.

So, the statements A) and B) are true.

6 0
3 years ago
Read 2 more answers
Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in Chemistry) demonstrated that nuclei were very small
Vaselesa [24]

Answer:

The final kinetic energy of the Helium nucleus (alpha particle) after been scattered through an angle of 120° is

8.00 x 10-13J

Explanation:

In Rutherford Scattering experiment, the collision of the helium nucleus with the gold nucleus is an ELASTIC COLLISION. This means that the kinetic energy is conserved ( The same before and after the collision).

Thus, the final kinetic energy of the helium nucleus is the same as initial kinetic energy (8.00 x 10^-13Joules)

Although, the kinetic energy is converted to potential energy in Coulomb's law equation.

That is,

1/2(mv^2) = (K* q1q2)/r

Where m is the mass of helium nucleus, v is its colliding velocity, k is electrostatic constant, q1 is the charge on helium nucleus, q2 is the charge on gold nucleus, r is impact parameter

6 0
3 years ago
What is the voltage of a motor that draws a current of 2 a and produces 240 w of power?
MA_775_DIABLO [31]
Here Power = Voltage * Current

So, Voltage = Power/Current

Put the values, 

V = 240/2

V = 120 V

In short, Your Final Answer would be: 120 Volts

Hope this helps!
8 0
3 years ago
A certain unbalanced force gives a 5kg object an acceleration of 15 m/s2. What would be the acceleration if the same force was a
stira [4]

Answer:

a2 = 2.5 m/s2

Explanation:

F1 = m1 a1 We use the same force so F1 = F2

= 5kg × 15m/s2 F2 = m2 a2

= 75N a2 is required

a2 = F2 / m2

= 75N / 30 kg

= 2.5 m/s2

7 0
3 years ago
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