Answer:
The angular velocity is 
Explanation:
From the question we are told that
The mass of the child is 
The radius of the merry go round is 
The moment of inertia of the merry go round is 
The angular velocity of the merry-go round is 
The position of the child from the center of the merry-go-round is 
According to the law of angular momentum conservation
The initial angular momentum = final angular momentum
So
=> 
Now 
is the initial moment of inertia of the system which is mathematically represented as
Where 
is the initial moment of inertia of the boy which is mathematically evaluated as
substituting values
Thus
Thus
Now
Where 
is the final moment of inertia of the boy which is mathematically evaluated as
substituting values
Thus
Thus
Hence
Answer:
answer the correct is B
Explanation:
For the interference phenomenon to occur, some conditions must be met.
* You must have a light in phase and coherent, for this you can for a light from an incandescent source through a single slit, the light that comes out is coherent
* This light must strike two slits
* the light that passes through the slits must hit a distant screen and be able to see the phenomenon of constructive interference
when examining the different answer the correct one is B
Answer:
Explanation:
From Hooke's law, 
Substistuting the values, 
you can ignore the minus sign, since it is there to state that the force is always in the opposite direction of the deformation, and has no influence otherwise, and your constant is 
Answer:
Strong base
Explanation:
A strong base usually has the pH of between 12 to 14
Answer:
2.5 m/s east
Explanation:
Let east be the positive direction for velocity.
The change in momentum of the 0.75 kg model car is ...
m1·v2 -m1·v1 = (0.75 kg)(11 m/s) -(0.75 kg)(-9 m/s)
= (0.75 kg)(20 m/s) = 15 kg·m/s
The change in momentum of the 2.0 kg model car is the opposite of this, so the total change in momentum is zero.
m2·v2 -m2·v1 = (2 kg)(v2 m/s) -(2 kg)(10 m/s) = 2(v2 -10) kg·m/s
The required relation is ...
15 kg·m/s = -2(v2 -10) kg·m/s
-7.5 = v2 -10 . . . . divide by -2
2.5 = v2 . . . . . . . add 10
The velocity of the model truck after the collision is 2.5 m/s east.
