(A) NF3 covalent compound
(B) BaO ionic bond.
(C) NH4)2CO3 ionic bond.
(D) Sr(H2PO4)2 covalent compound
(E) IBr covalent compound
(F) Na2O ionic bond.
<h3>What are a covalent compound and ionic bond?</h3>
Covalent bonds form when two or more additional nonmetals combine. For instance, both hydrogen and oxygen are nonmetals, and when they connect to make moisture, they do so by forming covalent bonds. Combinations that are composed of only non-metals or semi-metals with non-metals will demonstrate covalent bonding and will be classified as molecular combinations.
- As a broad rule of thumb, combinations that involve a metal binding with either a non-metal or a semi-metal will show ionic bonding. Therefore, the compound created from sodium and chlorine will be ionic (a metal and a non-metal). Nitrogen monoxide (NO) will be a covalently bound molecule (two non-metals), silicon dioxide (SiO2) will be a covalently bound molecule (a semi-metal and a non-metal) and MgCl2 will be ionic (a metal and a non-metal).
- A polyatomic ion is an ion comprised of two or more particles that have a commission as a group (poly = many). The ammonium ion (see figure below) consists of one nitrogen atom and four hydrogen atoms. Concurrently, they constitute a single ion with a 1+ charge and a formula of NH4+. The carbonate ion (see figure below) consists of one carbon particle and three oxygen atoms and maintains a comprehensive charge of 2−. The procedure of the carbonate ion is CO32−.
To learn more about covalent compound, refer to:
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Answer:
80.1 grams
Explanation:
Find the molar mass of CH3OH first by using the periodic table values.
12.011 g/mol C + (1.008*3 g/mol H) + 15.999g/mol O + 1.008 g/mol H
=32.042 so that is the molar mass
Now that you have 2.50 moles of CH3OH, you can calculate the mass in g
2.50molCH3OH * (32.042g CH3OH / 1 mol CH3OH) = 80.105
32.042g / 1 mol is the same as 32.042 g/mol
Since there are 3 sig figs in the problem (2.50 has 3 sig figs), you round to 80.1 g CH3OH
Explanation:
1)  + 7 H_2(g)](https://tex.z-dn.net/?f=%202%20Al%28s%29%20%2B%202%20NaOH%28aq%29%20%2B%206%20H_2O%28l%29%20%5Clongleftrightarrow%202%20Na%5BAl%28OH%29_4%5D%28aq%29%20%2B%207%20H_2%28g%29)
![Kc=\frac{[Na[Al(OH)_4]]^2*[H_2]^7}{[NaOH]^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BNa%5BAl%28OH%29_4%5D%5D%5E2%2A%5BH_2%5D%5E7%7D%7B%5BNaOH%5D%5E2%7D)
The Kc for the reverse reaction is the inverse of the Kc of the reaction:

2) 
![Kc=\frac{[H_2SO_4]}{[SO_3]^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_2SO_4%5D%7D%7B%5BSO_3%5D%5E2%7D)
The Kc for the reverse reaction is the inverse of the Kc of the reaction:

3)
![Kc=\frac{1}{[O_2]^3}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B1%7D%7B%5BO_2%5D%5E3%7D)
The Kc for the reverse reaction is the inverse of the Kc of the reaction:

<span>explain why the dissolved component does not settle out of a solution -
</span><span>Before saturation, there are attractive forces between solute and solvent. after saturation, the capacity for the attractive forces is reached and no more solute can be dissolved</span>