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Mekhanik [1.2K]
3 years ago
10

Which family of the periodic table forms ions with a -1 charge

Chemistry
1 answer:
Anon25 [30]3 years ago
5 0

Answer:

ur mom

sorry I had to :(((

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The half life of carbon is 5700 years. if you started with 100g of carbon 14 how much would remain after 4 half lives
kherson [118]
When dealing with a half life question, you should use the half life formula which is: y = a(b)^t/h
3 0
3 years ago
The reaction below shows the decomposition of sodium azide into sodium metal and nitrogen gas.
Komok [63]

Answer:

0.51g

Explanation:

Given parameters:

Volume of nitrogen gas  = 744mL

Unknown:

Mass of sodium metal produced = ?

Solution:

Let us assume that the gas, nitrogen was collected at STP which is the standard temperature and pressure, we can easily find its number of moles.

            Number of moles  = \frac{volume of gas}{22.4}

since the gas volume given is 744mL = 0.744mL

   Therefore input the variables;  

         Number of moles  = \frac{0.744}{22.4}   = 0.03moles

Now that we know the number of moles of the gas, let us revisit the reaction equation:

      2NaN₃   →   2Na    +  3N₂

It good to ensure that the reaction is balanced;

         3 mole of nitrogen gas is produced with 2 moles of Na

        0.03 mole of nitrogen gas will be produce with \frac{0.03 x 2}{3}  = 0.02mole

So;

       Using;

                    mass  = number of moles x molar mass

let us solve for the mass of Na;

                   molar mass of Na = 23g/mol

                  mass  = 0.02 x 23  = 0.51g

6 0
3 years ago
Qué concentración en % m/m tendrá una solución preparada con 20 g de NaCl (cloruro de sodio, sal común) y 200 g de agua?
alexgriva [62]

Answer:

\%m/m = 10\,\%

Explanation:

El porcentaje masa a masa de la solución se obtiene al dividir la masa del cloruro de sodio por la masa del agua (The mass-mass percentage of solution is obtained by dividing the mass of sodium chloride by the mass of water):

\%m/m = \frac{20\,g}{200\,g}\times 100\,\%

\%m/m = 10\,\%

4 0
3 years ago
A chemist must dilute 47.2 mL of 150. mM aqueous sodium nitrate solution until the concentration falls to . He'll do this by add
erma4kov [3.2K]

Answer:

0.295 L

Explanation:

It seems your question lacks the final concentration value. But an internet search tells me this might be the complete question:

" A chemist must dilute 47.2 mL of 150. mM aqueous sodium nitrate solution until the concentration falls to 24.0 mM. He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits. "

Keep in mind that if your value is different, the answer will be different as well. However the methodology will remain the same.

To solve this problem we can<u> use the formula</u> C₁V₁=C₂V₂

Where the subscript 1 refers to the concentrated solution and the subscript 2 to the diluted one.

  • 47.2 mL * 150 mM = 24.0 mM * V₂
  • V₂ = 295 mL

And <u>converting into L </u>becomes:

  • 295 mL * \frac{1 L}{1000mL} = 0.295 L

6 0
4 years ago
Which part of the human skeletal system is INCORRECTLY matched with its function?
stiks02 [169]
Hi the answer your looking for is C, muscle: bone to bone connection.
Hope this helps you.
8 0
4 years ago
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