Question

200.0 mL OF A 5.10 M solution are diluted to 500.0 mL. What is the concentration of the resulting solution? *

Answer 1

Answer:

Concentration of the resulting solution = 2.04 M

Explanation:

Data:

M1 = 5.10 M

V1 = 200.0 mL

V2 = 500.0 mL

M2 = ?

By modifying the volume of solution, keeping the amount of solute constant, the concentration changes. To perform the calculations, the equation will be:

$M1*V1=M2*V2$

Where M1 is the initial concentration of the solution, M2 the final concentration and V is the value of the volumes of the initial and final solution.

Clearing the value of M2 from the equation and replacing the values ​​we have:

$M2=\frac{M1*V1}{V2} =\frac{5.10M*200mL}{500mL} =2.04M$

Answer 2

Answer:

2.04M

Explanation:

Using C1V1 = C2V2

where;

C1 =  Concentration of stock solution  = 5.10M

C2 = Final concentration of new solution = x

V1 = Volume of stock solution = 200ml

V2 = Final volume of new solution = 500ml

Inserting the values into the formulae, we have;

5.10 * 200 = x * 500

x = (5.10 * 200) / 500

x = 2.04M