Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.032.03 times a second. A tack is stuck in the ti
1 answer:
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The first thing you should know is that acceleration is a vector, therefore, it has magnitude, and direction.
By definition, we have that the vector acceleration is given by:
Where,
dv/dt: derived from the velocity vector with respect to time,
Therefore, the units of the vector acceleration are:
The symbol of acceleration is:
Answer:
The statements about acceleration that are true are:
a. the si units of acceleration are m/s2.
b. for acceleration, you must have a number, a unit, and a direction.
d. the symbol for acceleration is (True, only if the symbol is the same as above)
Answer:
number of cycles = 4.68 × 10⁴ cycles
Explanation:
In damped RLC oscillation
voltage (V(t)) = V_o\ e^{-\dfrac{tR}{2L}}............(1)
given,
C = 0.17μF = 0.17 × 10⁻⁶ F
R = 1.4 Ω
L = 15 m H = 15 × 10⁻³ H V(t) = V₀/2
From the equation (1)
taking log both side
t = 14.85 sec
time period
T = 3.172 × 10⁻⁴
number of cycle =
=
number of cycles = 4.68 × 10⁴ cycles