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mafiozo [28]
3 years ago
11

Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.032.03 times a second. A tack is stuck in the ti

re at a distance of 0.357 m0.357 m from the rotation axis. Noting that for every rotation the tack travels one circumference, find the tack's tangential speed.
Physics
1 answer:
Luda [366]3 years ago
6 0

Answer:

4.55 m/s

Explanation:

The frequency is defined as the number of rotations in one second

So, f = 2.03 Hz

r = 0.357 m

The tangential speed is

v = r ω = r x 2 x 3.14 x f = 0.357 x 2 x 3.14 x 2.03 = 4.55 m/s

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A solenoid of length 0.35 m and diameter 0.040 m carries a current of 5.0 A through its windings. If the magnetic field in the c
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Correct question:

A solenoid of length 0.35 m and diameter 0.040 m carries a current of 5.0 A through its windings. If the magnetic field in the center of the solenoid is 2.8 x 10⁻² T, what is the number of turns per meter for this solenoid?

Answer:

the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.

Explanation:

Given;

length of solenoid, L= 0.35 m

diameter of the solenoid, d = 0.04 m

current through the solenoid, I = 5.0 A

magnetic field in the center of the solenoid, 2.8 x 10⁻² T

The number of turns per meter for the solenoid is calculated as follows;

B =\mu_o  I(\frac{N}{L} )\\\\B =  \mu_o  I(n)\\\\n = \frac{B}{\mu_o I} \\\\n = \frac{2.8 \times 10^{-2}}{4 \pi \times 10^{-7} \times 5.0} \\\\n = 4.5 \times 10^3 \ turns/m

Therefore, the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.

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3 years ago
A student uses the right-hand rule as shown.
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