The answer is; C
Conservation of matter in a reaction means that the mass of matter in the products is equal to the mass of the reactants. Energy/matter cannot be created or destroyed but converted from one form to another.
An expanding balloon with the increased evolution of gas is a good visible practical sign in the experiment on the conservation of matter in the reaction. As the magnesium disappears with an increased input of hydrochloric acid, the balloon gets bigger showing that more hydrogen is evolved from the reaction;
2HCL + Mg MgCl2 + H2
Answer:
If you add the masses of all the products after fission, they are LESS than the mass of the reactants.
Explanation:
A nuclear fission reaction is a radioactive reaction which in which a heavy nucleus spontaneously disintegrates into 2 lighter nuclei and some neutrons with a release of large amount of energy.
When nuclear fission occurs, a mass deficit between the decaying nuclei and the product occurs. It is this mass that actually yields the energy that is produced as a by product of the reaction.
Answer:
![V_{CO_2}=16.0mL](https://tex.z-dn.net/?f=V_%7BCO_2%7D%3D16.0mL)
Explanation:
Hello,
In this case, given that the same temperature and pressure is given for all the gases, we can notice that 16.0 mL are related with two moles of carbon monoxide by means of the Avogadro's law which allows us to understand the volume-moles relationship as a directly proportional relationship. In such a way, since in the chemical reaction:
![2CO(g)+O_2(g)\rightarrow 2CO_2(g)](https://tex.z-dn.net/?f=2CO%28g%29%2BO_2%28g%29%5Crightarrow%202CO_2%28g%29)
We notice two moles of carbon monoxide yield two moles of carbon dioxide, therefore we have the relationship:
![n_{CO}V_{CO}=n_{CO_2}V_{CO_2}](https://tex.z-dn.net/?f=n_%7BCO%7DV_%7BCO%7D%3Dn_%7BCO_2%7DV_%7BCO_2%7D)
Thus, solving for the yielded volume of carbon dioxide we obtain:
![V_{CO_2}=\frac{n_{CO}V_{CO}}{n_{CO_2}} =\frac{2mol*16.0mL}{2mol}\\ \\V_{CO_2}=16.0mL](https://tex.z-dn.net/?f=V_%7BCO_2%7D%3D%5Cfrac%7Bn_%7BCO%7DV_%7BCO%7D%7D%7Bn_%7BCO_2%7D%7D%20%3D%5Cfrac%7B2mol%2A16.0mL%7D%7B2mol%7D%5C%5C%20%5C%5CV_%7BCO_2%7D%3D16.0mL)
Best regards.
Answer:
filtration and Chromatography
Explanation:
The first method used for separation of solids from the mixture is filtration. Filtration is used to separate different solids in a mixture which has particles of different sizes. Other method is Chromatography in which the compounds in the mixtures are separated from each other by moving the mixture at high speed. Due to high speed, the compounds are separated from each other because different compounds have different speeds so it is separated easily.
Answer : The mass of reactant
remain would be, 0.20 grams.
Solution : Given,
Moles of
= 0.40 mol
Moles of
= 0.15 mol
Molar mass of
= 2 g/mole
First we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
![2H_2+O_2\rightarrow 2H_2O](https://tex.z-dn.net/?f=2H_2%2BO_2%5Crightarrow%202H_2O)
From the balanced reaction we conclude that
As, 1 mole of
react with 2 mole of ![H_2](https://tex.z-dn.net/?f=H_2)
So, 0.15 moles of
react with
moles of ![H_2](https://tex.z-dn.net/?f=H_2)
From this we conclude that,
is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
The moles of reactant
remain = 0.40 - 0.30 = 0.10 mole
Now we have to calculate the mass of reactant
remain.
![\text{ Mass of }H_2=\text{ Moles of }H_2\times \text{ Molar mass of }H_2](https://tex.z-dn.net/?f=%5Ctext%7B%20Mass%20of%20%7DH_2%3D%5Ctext%7B%20Moles%20of%20%7DH_2%5Ctimes%20%5Ctext%7B%20Molar%20mass%20of%20%7DH_2)
![\text{ Mass of }H_2=(0.10moles)\times (2g/mole)=0.20g](https://tex.z-dn.net/?f=%5Ctext%7B%20Mass%20of%20%7DH_2%3D%280.10moles%29%5Ctimes%20%282g%2Fmole%29%3D0.20g)
Therefore, the mass of reactant
remain would be, 0.20 grams.