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maksim [4K]
4 years ago
13

Eugene is studying the levels of structural organization of an animal’s body. Which level would describe a dog’s eye

Physics
2 answers:
mrs_skeptik [129]4 years ago
6 0
The levels of structural organization:
cell ---> tissue ---> organ ---> organ system ---> organism

A dog's eye would be an organ.
natima [27]4 years ago
6 0
I think it's an organ.

Hope this helps !

Photon
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. Maria walked 1.5 miles south to her house in 0.5 hours. What is her speed in miles per hour?
Simora [160]

1) 3 miles/Hour

The speed is defined as the distance covered divided by the time taken:

v=\frac{d}{t}

where

d = 1.5 mi is the distance

t = 0.5 h is the time taken

Substituting,

v=\frac{1.5}{0.5}=3 mi/h

2) 1.34 m/s south

Velocity, instead, is a vector, so it has both a magnitude and a direction. We have:

d=1.5 mi \cdot 1609 m/mi = 2414 m is the displacement in meters

t=0.5 h \cdot 3600 s/h =1800 s is the time taken in seconds

Substituting,

v=\frac{2414 m}{1800 s}=1.34 m/s

And the direction of the velocity is the same as the displacement, so it is south.

6 0
4 years ago
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Art [367]

Answer:

poet

Explanation:

4 0
3 years ago
When air is heated, it will MOST likely
Alchen [17]

Answer:

B

Explanation:

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6 0
3 years ago
Read 2 more answers
You walk 60m east and then 20m at 20 degrees south of west. What is your displacement?
stich3 [128]
Let north and east be posetive
Y=20sin20
=6.840402867 south
X=20cos20
18.79385243 west
Net horizontal components=60+(-18.79)
=41.20614758m
Net vertical=-6.84040267
X^2=41.20614758^2+(-6.684040267)^2
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5 0
3 years ago
A cat dozes on a stationary merry-go-round, at a radius of 5.7 m from the center of the ride. Then the operator turns on the rid
tatyana61 [14]

Answer:

0.76

Explanation:

we are given:

radius (r) =5.7 m

speed (s) = 1 revolution in 5.5 seconds

acceleration due to gravity (g) = 9.8 m/s^{2}

coefficient of friction (Uk) = ?

 we can get the minimum coefficient of friction from the equation below

centrifugal force = frictional force

m x r x ω^{2} = Uk x m x g

r x ω^{2} = Uk x g

Uk = \frac{ r x ω^{2} }{g}

where ω (angular velocity) = \frac{2π}{time}

= \frac{2π }{5.5} = 1.14

Uk = \frac{ 5.7 x 1.14^{2} }{9.8} = 0.76

6 0
4 years ago
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