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Aloiza [94]
3 years ago
9

How are selective breeding, cloning, and genetic engineering similar? They are all controlled by nature. They are all controlled

by humans. They all begin with the use of udder cells. They all involve the use of enzymes that cut DNA.
Chemistry
2 answers:
sveticcg [70]3 years ago
7 0

Answer:They are all controlled by the human beings.

Explanation:

The selective breeding, cloning and genetic engineering are some of the techniques which is induced by the human efforts.

In case of selective breeding the male and female species having the selective characters are mated with each other so that the offspring produced  has the desired characters. It neither requires any enzyme nor uses udder cells.

In case of genetic engineering, the gene of interest is inserted in the bacterial species by the help of vector so that when the bacterial species amplify the gene of interest. This is how the desired products are produced by bacterial species. Example: Insulin production.

Cloning can be defined as another technique made by human beings in which the genetically identical species is made naturally or artificially for the benefit of the mankind.

evablogger [386]3 years ago
7 0

Answer:

b, they are controlled by humans

Explanation:

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What would be the result on the Insect population if the Bats and Mice were removed?
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3 years ago
How many CaF are in a 1.7x10^25 please I need help fast!!
Gemiola [76]
<h3>Answer:</h3>

28 mol CaF

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.7 × 10²⁵ molecules CaF

[Solve] moles CaF

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                          \displaystyle 1.7 \cdot 10^{25} \ molecules \ CaF(\frac{1 \ mol \ CaF}{6.022 \cdot 10^{23} \ molecules \ CaF})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 28.2298 \ moles \ CaF

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

28.2298 mol CaF ≈ 28 mol CaF

7 0
3 years ago
Does anybody know how to do this if so please help !
Viktor [21]

Answer:

add x to 7 and divide by 3

Explanation:

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3 0
3 years ago
If 45.0 mL of a 0.0500 M HNO3, 10.0 mL of a 0.0500 M KSCN, and 30.0 mL of a 0.0500 M Fe(NO3)3 are combined, what is the initial
jeka94

Answer:

the  initial concentration of SCN- in the mixture is 0.00588 M

Explanation:

The computation of the initial concentration of the SCN^- in the mixture is as follows:

As we know that

KSCN \rightarrow K^ + SCN^-

As it is mentioned in the question that KSCN is present 10 mL of 0.05 M

So, the total milimoles of SCN^- is

= 10 × 0.05

= 0.5  m moles

The total volume in mixture is

= 45 + 10 + 30

= 85 mL

Now the initial concentration of the SCN^- is

= 0.5 ÷ 85

= 0.00588 M

hence, the  initial concentration of SCN- in the mixture is 0.00588 M

5 0
3 years ago
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