Question

Ballon volume of 3200ml of xenon gas is at a gauge pressure of 122kPa and a temperature of 27c. What is the volume when the balloon is heated to 65c and Guage pressure decreased to 112 kpa?

Answer 1

Given:

The initial volume of the gas, V₁=3200 ml=3.2×10⁻³ m³

The initial pressure of the gas, P₁=122 kPa

The initial temperature of the gas, T₁=27 °C=300 K

The final temperature, T₂=65 °C=338 K

The final pressure, P₂=112 kPa

To find:

The final volume of xenon gas.

Explanation:

From the combined gas law,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

Where V₂ is the volume after it is heated.

On rearranging the above equation,

$V_2=\frac{T_2P_1V_1}{T_1P_2}$

On substituting the known values,

$\begin{gathered} V_2=\frac{338\times112\times10^3\times3.2\times10^{-3}}{300\times112\times10^3} \\ =3.61\text{ m}^3 \end{gathered}$

Final answer:

The volume of the balloon when it is heated is 3.61 m³