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aleksley [76]
3 years ago
5

12. In a gas mixture consisting of carbon dioxide (CO2) and nitrogen (N2), the carbon dioxide molecules have a root-mean-square

speed of 550 m/s. What is the root-mean-square speed of the nitrogen molecules in the sample? CO2 has a molar mass of 44 grams, and N2 has a molar mass of 28 grams. a) 627 m/s b) 752 m/s c) 564 m/s d) 821 m/s e) 689 m/s
Chemistry
1 answer:
zaharov [31]3 years ago
7 0

Answer:

The correct answer is option e.

Explanation:

The formula used for root mean square speed is:

\nu_{rms}=\sqrt{\frac{3kN_AT}{M}}

where,

\nu_{rms} = root mean square speed

k = Boltzmann’s constant = 1.38\times 10^{-23}J/K

T = temperature

M = Molar mass

N_A = Avogadro’s number = 6.02\times 10^{23}mol^{-1}

Root mean square speed of  carbon dioxide molecule:

\nu_{rms}= 550 m/s

Temperature of the mixture = T =?

Molar mass of carbon dioxide = 44 g/mol = 0.044 kg/mol

\nu_{rms}=550 m/s=\sqrt{\frac{3\times 1.38\times 10^{-23}J/K\times 6.022\times 10^{23}mol^{-1}T}{0.044 kg/mol}}

T = 533.87 K

Root mean square speed of nitrogen  molecule:

\nu'_{rms}= ?s

Molar mass of nitrogen = 28 g/mol = 0.028 kg/mol

\nu'_{rms}=\sqrt{\frac{3\times 1.38\times 10^{-23}J/K\times 6.022\times 10^{23}mol^{-1}\times 533.87 K}{0.028 kg/mol}}

\nu'_{rms}=689.46 m/s\approx 689 m/s

689 m/s is the root-mean-square speed of the nitrogen molecules in the sample.

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Answer:

2d

Explanation:

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8 0
2 years ago
Provide the name(s) for the tertiary alcohol(s) with the chemical formula C6H14O that have a 4-carbon chain. Although stereochem
pochemuha

Answer:

Explanation:

A tertiary alcohol is a compound (an alcohol) in which the carbon atom that has the hydroxyl group (-OH) is also bonded (saturated) to three different carbon atoms.

Based on the question, the only <u>tertiary alcohol that can result from C₆H₁₄O that have a 4-carbon chain</u> is

2-hydroxy-2,3-dimethylbutane

     H  OH   H    H

      |     |       |      |

H - C - C -   C  - C - H

      |     |       |      |

     H  CH₃  CH₃ H

From the above, we can see that the carbon atom having the hydroxyl group is also bonded to three other carbon atoms. And since we aren't considering stereochemistry, this is the only tertiary alcohol we can have with a 4-carbon chain

4 0
3 years ago
Omg GUYS I NEED HELPPP
Ilia_Sergeevich [38]

27) Partial pressure of oxygen: 57.8 kPa

29) Final volume: 80 mL

30) Final volume: 8987 L

31) Due to property of water of being polar, ice floats on water

Explanation:

27)

In a mixture of gases, the total pressure of the mixture is the sum of the partial pressures:

p_T = p_1 + p_2 + ... + p_N

In this problem, the mixture contains 3 gases (helium, carbon dioxide and oxygen). We know that the total pressure is

p_T=201.4 kPa

We also know the partial pressures of helium and carbon dioxide:

P_{He}=125.4 kPa\\P_{CO_2}=18.2 kPa

The total pressure can be written as

p_T=p_{He}+p_{CO_2}+p_{O_2}

where p_{O_2} is the partial pressure of oxygen. Therefore, we find

p_{O_2}=p_T-p_{He}-p_{CO_2}=201.4-125.4-18.2=57.8 kPa

29)

Assuming that the pressure of the gas is constant, we can apply Charle's law, which states that:

"For an ideal gas at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically,

\frac{V}{T}=const.

where

V is the volume of the gas

T is the Kelvin temperature

We can re-write it as

\frac{V_1}{T_1}=\frac{V_2}{T_2}

Here we have:

V_1 = 42 mL (initial volume)

T_1=-89^{\circ}C+273=184 K is the initial temperature

T_2=77^{\circ}C+273=350 K is the final temperature

Solving for V2, we find the final volume:

V_2=\frac{V_1 T_2}{T_1}=\frac{(42)(350)}{184}=80 mL

30)

For this problem, we can use the equation of state for ideal gases, which can be written as

\frac{p_1 V_1}{T_1}=\frac{p_2 V_2}{T_2}

where in this problem:

p_1 = 102.3 kPa is the initial pressure

V_1=1975 L is the initial volume

T_1=25^{\circ}C+273=298 K is the initial temperature

p_2=21.5 kPa is the final pressure

T_2=12^{\circ}C+273=285 K is the final temperature

And solving for V2, we find the final volume of the balloon:

V_2=\frac{p_1 V_1 T_2}{p_2 T_1}=\frac{(102.3)(1975)(285)}{(21.5)(298)}=8987 L

31)

A molecule of water consists of two atoms hydrogen bond with an atom of oxygen (H_2 O) in a covalent bond.

While the molecul of water is overall neutral, due to the higher electronegativity of the oxygen atom, electrons are slightly shifted towards the oxygen atom; as a result, there is a slightly positive charge on the hydrogen side, and a slightly negative charge on the oxygen side (so, the molecules is said to be polar).

As a consequence, molecules of water attract each other, forming the so-called "hydrogen bonds".

One direct consequence of the polarity of water is that ice floats on liquid water.

Normally, for every substance on Earth, the solid state is more dense than the liquid state. However, this is not true for water, because ice is less dense than liquid water.

This is due to the polarity of water. In fact, when the temperature of water is decreased to freezing point and water becomes ice, the hydrogen bondings "force" the molecules to arrange in a lattice structure, so that the molecules become more spaced when they turn into solid state. As a result, ice occupies more volume than water, and therefore it is less dense, being able to float on water.

Learn more about ideal gases:

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brainly.com/question/7316997

brainly.com/question/3658563

#LearnwithBrainly

4 0
3 years ago
Write a balanced chemical equation for the standard formation reaction of gaseous dinitrogen tetroxide n2o4 .
eduard
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3 0
3 years ago
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The ionization energy is the energy needed to remove an electron from an atom. In the bohr model of the hydrogen atom, this mean
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The ionization energy for a hydrogen atom in the n = 2 state is 328 kJ·mol⁻¹.

The <em>first ionization energy</em> of hydrogen is 1312.0 kJ·mol⁻¹.

Thus, H atoms in the <em>n</em> = 1 state have an energy of -1312.0 kJ·mol⁻¹ and an energy of 0 when <em>n</em> = ∞.

According to Bohr, Eₙ = k/<em>n</em>².

If <em>n</em> = 1, E₁= k/1² = k = -1312.0 kJ·mol⁻¹.

If <em>n</em> = 2, E₂ = k/2² = k/4 = (-1312.0 kJ·mol⁻¹)/4 = -328 kJ·mol⁻¹

∴ The ionization energy from <em>n</em> = 2 is 328 kJ·mol⁻¹ .

6 0
3 years ago
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