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aleksley [76]
3 years ago
5

12. In a gas mixture consisting of carbon dioxide (CO2) and nitrogen (N2), the carbon dioxide molecules have a root-mean-square

speed of 550 m/s. What is the root-mean-square speed of the nitrogen molecules in the sample? CO2 has a molar mass of 44 grams, and N2 has a molar mass of 28 grams. a) 627 m/s b) 752 m/s c) 564 m/s d) 821 m/s e) 689 m/s
Chemistry
1 answer:
zaharov [31]3 years ago
7 0

Answer:

The correct answer is option e.

Explanation:

The formula used for root mean square speed is:

\nu_{rms}=\sqrt{\frac{3kN_AT}{M}}

where,

\nu_{rms} = root mean square speed

k = Boltzmann’s constant = 1.38\times 10^{-23}J/K

T = temperature

M = Molar mass

N_A = Avogadro’s number = 6.02\times 10^{23}mol^{-1}

Root mean square speed of  carbon dioxide molecule:

\nu_{rms}= 550 m/s

Temperature of the mixture = T =?

Molar mass of carbon dioxide = 44 g/mol = 0.044 kg/mol

\nu_{rms}=550 m/s=\sqrt{\frac{3\times 1.38\times 10^{-23}J/K\times 6.022\times 10^{23}mol^{-1}T}{0.044 kg/mol}}

T = 533.87 K

Root mean square speed of nitrogen  molecule:

\nu'_{rms}= ?s

Molar mass of nitrogen = 28 g/mol = 0.028 kg/mol

\nu'_{rms}=\sqrt{\frac{3\times 1.38\times 10^{-23}J/K\times 6.022\times 10^{23}mol^{-1}\times 533.87 K}{0.028 kg/mol}}

\nu'_{rms}=689.46 m/s\approx 689 m/s

689 m/s is the root-mean-square speed of the nitrogen molecules in the sample.

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5.82 760.<br> Х<br> 425.976<br> answer should have<br> sig.figs.<br> calculated answer:
Mekhanik [1.2K]

Answer:

2482.4177376

Explanation:

1: 5.82 760  times   425.976

2: You will find the answer that is 2482.4177376

<em><u>Hope this helps.</u></em>

7 0
3 years ago
a 160 milligram sample of a radioactive isotope decays to 10 kilograms in 12 years. what is the half life of this element
Shkiper50 [21]

Answer:

3 years

Explanation:

Given data:

Initial amount of sample = 160 Kg

Amount left after 12 years = 10 Kg

Half life = ?

Solution:

at time zero = 160 Kg

1st half life = 160/2 = 80 kg

2nd half life = 80/2 = 40 kg

3rd half life = 40 / 2 = 20 kg

4th half life = 20 / 2 = 10 kg

Half life:

HL = elapsed time / half life

12 years / 4 = 3 years

8 0
4 years ago
4) What volume will the gas in the balloon at right occupy at 250k?<br><br> balloon: 4.3L 350K
swat32

Answer:

2.87 liter.

Explanation:

Given:

Initially volume of balloon = 4.3 liter

Initially temperature of balloon = 350 K

Question asked:

What volume will the gas in the balloon occupy at 250 K ?

Solution:

By using:

Pv =nRT

Assuming pressure as constant,

V∝ T

Now, let  K is the constant.

V = KT

Let initial volume of balloon , V_{1} = 4.3 liter

1000 liter = 1 meter cube

1 liter = \frac{1}{1000} m^{3} = 10^{-3} m^{3

4.3 liter = 4.3\times10^{-3}=4.3\times10^{-3} m^{3}

And initial temperature of balloon, T_{1} = 350 K

Let the final volume of balloon is V_{2}

And as given, final temperature of balloon, T_{2} is 250 K

Now, V_{1} = KT_{1}

4.3\times10^{-3}=K\times350\ (equation\ 1 )

V_{2} = KT_{2}

=K\times250\ (equation 2)

Dividing equation 1 and 2,

\frac{4.3\times10^{-3}}{V_{2} } =\frac{K\times350}{K\times250}

K cancelled by K.

By cross multiplication:

350V_{2} =4.3\times10^{-3} \times250\\V_{2} =\frac{ 4.3\times10^{-3} \times250\\}{350} \\          = \frac{1075\times10^{-3}}{350} \\          =2.87\times10^{-3}m^{3}

Now, convert it into liter with the help of calculation done above,

2.87\times10^{-3} \times1000\\2.87\times10^{-3} \times10^{3} \\2.87\ liter

Therefore, volume of the gas in the balloon at 250 K will be  2.87 liter.

4 0
4 years ago
15 points!
Alex_Xolod [135]

Answer:

C: It is the difference between the total kinetic and potential energy in a system.

Explanation:

6 0
3 years ago
What is the volume of 425g of ice if the density is 0.92g/mL
Sati [7]
Density=mass/ volume so you solve for volume and get 461.96 mL
6 0
4 years ago
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