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4 years ago

The measure of the amount of dissolved salt in a liquid sample is called

Chemistry

1 answer:

Ann [662]4 years ago

7 0

The answer is salinity, salinity is the saltiness or dissolved inorganic salt content of a body of water.

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HELP IM CONFUSED I GIVE BRAINLIEST

alisha [4.7K]

Answer:

I⁻ , Sr²⁺ , K⁺

Explanation:

refer to the periodic table and memorize trends in charges.

7 0

4 years ago

The common Eastern mole, a mammal, typically has a mass of 83 g, which corresponds to about 8.3 moles of atoms. (A mole of atoms

Alchen [17]

Answer:

1.6605 × 10⁻²³ g / atom , 9.99 amu

Explanation:

Atoms present in 1 mole = 6.022 × 10²³ atoms

Given that

Moles of common Eastern mole = 8.3 moles

So,

Atoms in 8.3 moles are:

8.3 moles = 6.022 × 10²³ × 8.3 atoms

Also,

Average mass = Mass of the sample / Number of atoms

Mass of sample = 83 g

Average mass = 83 g / 6.022 × 10²³ × 8.3 atoms = 1.6605 × 10⁻²³ g / atom

In amu :

1 amu = 1.66 × 10⁻²⁴ g / atom

So,

Average mass = 1.6605 × 10⁻²³ / 1.66 × 10⁻²⁴ amu = 9.99 amu

6 0

3 years ago

What is your opinion on Mercury element

elixir [45]

Answer:

Mercury is an liquid metal

Explanation:

Mercury is a chemical element with the symbol Hg and atomic number 80. It is commonly known as quicksilver and was formerly named hydrargyrum.

Symbol: Hg

7 0

3 years ago

11) The pH of an aqueous solution of hydrochloric acid is 2. What will be the pH of the acid after the

romanna [79]

C) 7 ...............

3 0

3 years ago

Consider the reaction below for which K = 78.2 atm-1. A(g) + B(g) ↔ C(g) Assume that 0.386 mol C(g) is placed in the cylinder re

borishaifa [10]

Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

A + B ⇄ C

where;

numbers of moles = 0.386 mol C (g)

Volume = 7.29 L

Molar concentration of C = $\frac{0.386}{7.29}$

= 0.053 M

A + B ⇄ C

Initial 0 0 0.530

Change +x +x - x

Equilibrium x x (0.0530 - x)

$K = \frac{[C]}{[A][B]}$

where

K is given as ; 78.2 atm-1.

So, we have:

$78.2=\frac{[0.0530-x]}{[x][x]}$

$78.2= \frac{(0.0530-x)}{(x^2)}$

$78.2x^2= 0.0530-x$

$78.2x^2+x-0.0530=0$

Using quadratic formula;

$\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where; a = 78.2 ; b = 1 ; c= - 0.0530

= $\frac{-b+\sqrt{b^2-4ac} }{2a}$ or $\frac{-b-\sqrt{b^2-4ac} }{2a}$

= $\frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}$ or $\frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}$

= 0.0204 or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

= 0.0530 - 0.0204

= 0.0326

Total number of moles at equilibrium = 0.0204 + 0.0204 + 0.0326

= 0.0734

Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT

if we make V the subject of the formula; we have:

$V = \frac{nRT}{P}$

where;

P (pressure) = 1 atm

n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K (fixed constant temperature )

V (volume) = ???

$V=\frac{(0.0734*0.0821*273.15)}{(1.00)}$

V = 1.64604

V ≅ 1.65 L

3 0

3 years ago