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IrinaVladis [17]
3 years ago
13

Which radioactive isotope would take the least amount of time to become stable? rubidium-91 iodine-131 cesium-135 uranium-238

Chemistry
2 answers:
Masteriza [31]3 years ago
5 0
The answer is rubidium -91 because it takes a shorter time of 58.4 seconds to become stable.
DanielleElmas [232]3 years ago
5 0

Answer:

the answer is A

Explanation:

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wrapping a boiled water keeps the water hot..cus it's wrapped and no air can go out

3 0
2 years ago
4NH3 + 5O2-&gt; 4NO + 6H2O<br><br> How many molesof NO are formed if 824g of NH3 react ?
ZanzabumX [31]
824 g NH3 (1 mol/17 g NH3) (4 mol NO/4mol NH3)

48.47 moles NO
4 0
3 years ago
If 3.00 g of aluminum hydroxide reacts with 1.40 g of sulfuric acid, what is the mass of water produced?
Leokris [45]
The Law of Conservation of Mass states that matter is not created nor destroyed.

Based on this, we can use some addition to find the answer.

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Hope this helps :)
4 0
3 years ago
A sample of polonium-210 has an initial mass of 390 milligrams (mg). If the half-life of polonium-210 is 36 days, how many mg of
kondaur [170]

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5 0
2 years ago
Read 2 more answers
19. What is sthe mass of 6.02 x 1024 atoms
alekssr [168]

The mass of magnesium in 6.02 \times 10^{24} atoms is 240 g.

Answer: Option A

<u>Explanation:</u>

First, we have to convert the atoms to moles of magnesium.

We know that 6.02 \times 10^{24} atoms are present in 1 mole of magnesium. So,

    \text { 1 atom }=\frac{1}{6.02 \times 10^{24}} \text { moles }

    6.02 \times 10^{24} \text { atoms }=\frac{6.02 \times 10^{24}}{6.02 \times 10^{23}} \text { moles }=10 \text { moles }

Thus,

     Mass of M g= molar mass of M g \times No. of moles of M g

     \text { Mass of } M g=24 \times 10=240 g

Thus, 240 g of Magnesium is present in 6.02 \times 10^{24} atoms.

4 0
3 years ago
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