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3 years ago

Which radioactive isotope would take the least amount of time to become stable? rubidium-91 iodine-131 cesium-135 uranium-238

Chemistry

2 answers:

Masteriza [31]3 years ago

5 0

The answer is rubidium -91 because it takes a shorter time of 58.4 seconds to become stable.

DanielleElmas [232]3 years ago

5 0

Answer:

the answer is A

Explanation:

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3 years ago

A 1.555-g sample of baking soda decomposes with heat to produce 0.991 g Na2CO3. Refer to Example Exercise 14.l and show the calc

Sunny_sXe [5.5K]

Answer:

a) 101%

b)59.7%

Explanation:

The equation for the thermal decomposition of baking soda is shown;

2NaHCO3 → Na2CO3 + H2O + CO2

Number of moles of baking soda= mass/molar mass= 1.555g/84.007 g/mol = 0.0185 moles

From the reaction equation;

2 moles of baking soda yields 1 mole of sodium carbonate

0.0185 moles of baking soda will yield = 0.0185 moles ×1 /2 = 9.25 ×10^-3 moles of sodium carbonate.

Therefore, mass of sodium carbonate= 9.25 ×10^-3 moles × 106gmol-1= 0.9805 g of sodium carbonate. This is the theoretical yield of sodium carbonate.

%yield = actual yield/theoretical yield ×100

% yield = 0.991/0.9805 ×100

%yield = 101%

Since ;

2NaHCO3 → Na2CO3 + H2O + CO2

And H2O + CO2 ---> H2CO3

Hence I can write, 2NaHCO3 → Na2CO3 + H2CO3

Molar mass of H2CO3= 62.03 gmol-1

Molar mass of baking soda= 84 gmol-1

Therefore, mass of baking soda=

0.325/62.03 × 2 × 84 = 0.88 g of NaHCO3

% of NaHCO3= 0.88/1.473 × 100 = 59.7%

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3 years ago

Draw the major organic product for the reaction of 1-phenylpropan-1-one with the provided phosphonium ylide.

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Answer:

2-methylene propylbenzene

Explanation:

The Wittig Reaction is a reaction that converts aldehydes and ketones into alkenes through reaction with a phosphorus ylide.

The ketone in this case is 1-phenylpropan-1-one. The provided phosphonium ylide is shown in the image attached. The reaction involves;

i) alkylation

ii) addition

The product of the major organic product of the reaction is 2-methylene propylbenzene.

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