If an electron moves up from the first orbit to the higher energy levels, energy will be absorbed by the electron itself and no emission line produced.
But if it moves from the orbits 6,5,4 and 3 to orbit 2, energy will be released by the electron and different emission lines wll be produced.
2-bromo-2-methylpropane should have reacted faster.
The actual neutralization reaction between the acid and base is H+ + OH- = H2O and this is what the -56 kJ/mole applies to
Then work out how much reactants you have
0.150 L * 0.50 mole/L = 0.075 mole for HCl
0.050 L * 1.00 mole/L = 0.050 mole for NaOH
So the HCl is in excess and the NaOH will all react. The energy released is -56 kJ/mole * 0.050 mole = -2.8 kJ or -2800 J
Temperature changes of solid, liquids or gas are calculated using:
energy = mass * heat capacity * (initial temperature - final temperature)
-2800 J = 200g * 4.18 J/gC * (53.9C - Tf)
Tf = 57.25 C. Rounded off I would say 57.3 C
Answer:
Chemical formula the formula is mnSO4
Explanation: