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Valentin [98]
3 years ago
5

Katy wrote the following examples of changes in substances. Example A: Butter melts on warm toast. Example B: Drink mix dissolve

s in water. Which statement is correct? Both are examples of physical changes. Both are examples of chemical changes. Example A describes a physical change and Example B describes a chemical change. Example A describes a chemical change and Example B describes a physical change.
Chemistry
2 answers:
FinnZ [79.3K]3 years ago
8 0
A= Physical Change
B=Chemical Change
Rasek [7]3 years ago
5 0

Answer:

Example A describes a physical change and Example B describes a chemical change.

Explanation:

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What is the new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm?
Volgvan

Answer: The new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.

Explanation:

Given: V_{1} = 61 L,      T_{1} = 183 K,      P_{1} = 0.60 atm

At STP, the value of pressure is 1 atm and temperature is 273.15 K.

Now, formula used to calculate the new volume is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{0.60 atm \times 61 L}{183 K} = \frac{1 atm \times V_{2}}{273.15 K}\\V_{2} = 54.63 L

Thus, we can conclude that the new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.

4 0
3 years ago
Refer to the following balanced equation in which ammonia reacts with nitrogen monoxide to produce nitrogen and water.
RSB [31]

Answer:4314

Explanation:

6 0
3 years ago
Match the following terms:
AURORKA [14]

Answer:

See below ~

Explanation:

<u>A to B</u>

⇒ Solid Phase

==========================================================

<u>B to C</u>

⇒ Melting

==========================================================

<u>C to D</u>

⇒ Liquid Phase

==========================================================

<u>D to E</u>

⇒ Vaporizing

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<u>E to F and beyond</u>

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3 0
2 years ago
Unscramble the word acdeeilpsz–​
lana [24]

Answer:

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3 0
3 years ago
The freezing-point depression of a 0.100 m MgSO4 solution is 0.225°C. Determine the experimental van't Hoff factor of MgSO4 at t
Andrews [41]

<u>Answer:</u> The experimental van't Hoff factor is 1.21

<u>Explanation:</u>

The expression for the depression in freezing point is given as:

\Delta T_f=iK_f\times m

where,

i = van't Hoff factor = ?

\Delta T_f = depression in freezing point  = 0.225°C

K_f = Cryoscopic constant  = 1.86°C/m

m = molality of the solution = 0.100 m

Putting values in above equation, we get:

0.225^oC=i\times 1.86^oC/m\times 0.100m\\\\i=\frac{0.225}{1.86\times 0.100}=1.21

Hence, the experimental van't Hoff factor is 1.21

7 0
3 years ago
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