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Anton [14]
2 years ago
15

What is the maximum number of electrons in an atom n=4 l=1 ml=0

Chemistry
1 answer:
Nitella [24]2 years ago
4 0

Answer:

18 electrons

Explanation:

when l=1, this tell you that it is "p sub shell"

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How many moles of carbon dioxide are produced from 8.73 moles of tristearin?​
matrenka [14]

Answer:

Explanation:

  8.73 mol                                         x mol

2 C57H110O6(S) + 163 O2(g)  --->  114 CO2(g) + 110 H2O(I)

2 mol                                               114 mol

8.78 mol (114mol/2 mol) =500.46 mol

8 0
3 years ago
Saturated fatty acids and unsaturated fatty acids differ in.
ratelena [41]

Answer:

the number off double bonds in a fatty acid chain

4 0
2 years ago
A 99.8 mL sample of a solution that is 12.0% KI by mass (d: 1.093 g/mL) is added to 96.7 mL of another solution that is 14.0% Pb
andre [41]

Answer:

m_{PbI_2}=18.2gPbI_2

Explanation:

Hello,

In this case, we write the reaction again:

Pb(NO_3)_2(aq) + 2 KI(aq)\rightarrow PbI_2(s) + 2 KNO_3(aq)

In such a way, the first thing we do is to compute the reacting moles of lead (II) nitrate and potassium iodide, by using the concentration, volumes, densities and molar masses, 331.2 g/mol and 166.0 g/mol respectively:

n_{Pb(NO_3)_2}=\frac{0.14gPb(NO_3)_2}{1g\ sln}*\frac{1molPb(NO_3)_2}{331.2gPb(NO_3)_2}  *\frac{1.134g\ sln}{1mL\ sln} *96.7mL\ sln\\\\n_{Pb(NO_3)_2}=0.04635molPb(NO_3)_2\\\\n_{KI}=\frac{0.12gKI}{1g\ sln}*\frac{1molKI}{166.0gKI}  *\frac{1.093g\ sln}{1mL\ sln} *99.8mL\ sln\\\\n_{KI}=0.07885molKI

Next, as lead (II) nitrate and potassium iodide are in a 1:2 molar ratio, 0.04635 mol of lead (II) nitrate will completely react with the following moles of potassium nitrate:

0.04635molPb(NO_3)_2*\frac{2molKI}{1molPb(NO_3)_2} =0.0927molKI

But we only have 0.07885 moles, for that reason KI is the limiting reactant, so we compute the yielded grams of lead (II) iodide, whose molar mass is 461.01 g/mol, by using their 2:1 molar ratio:

m_{PbI_2}=0.07885molKI*\frac{1molPbI_2}{2molKI} *\frac{461.01gPbI_2}{1molPbI_2} \\\\m_{PbI_2}=18.2gPbI_2

Best regards.

5 0
3 years ago
Read 2 more answers
Using principles of atomic structure, explain why the atomic radius of Te is less than the ionic radius of Te2− . Photoelectron
ValentinkaMS [17]

Answer:

See explanation

Explanation:

Let us recall that a negative ion is formed by addition of electrons to an atom. When electrons are added to the atom, greater interelectronic repulsion increases the size of the Te^2− hence it is greater in size than Te atom. Therefore, the ionic radius of Te^2− is greater than the atomic radius of Te.

In the second question, oxygen is positioned so far to the right because it has a far smaller nuclear charge compared to Te. Hence in the PES spectrum, the 1s sublevel of oxygen lies far to the right of that of Te.

3 0
3 years ago
How many molecules are in 2.00 moles of H20????????
Elis [28]

2x 6.022x10^23= 1.204x10^24

7 0
3 years ago
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