Answer:
pH = 6.999
The solution is acidic.
Explanation:
HBr is a strong acid, a very strong one.
In water, this acid is totally dissociated.
HBr + H₂O → H₃O⁺ + Br⁻
We can think pH, as - log 7.75×10⁻¹² but this is 11.1
acid pH can't never be higher than 7.
We apply the charge balance:
[H⁺] = [Br⁻] + [OH⁻]
All the protons come from the bromide and the OH⁻ that come from water.
We can also think [OH⁻] = Kw / [H⁺] so:
[H⁺] = [Br⁻] + Kw / [H⁺]
Now, our unknown is [H⁺]
[H⁺] = 7.75×10⁻¹² + 1×10⁻¹⁴ / [H⁺]
[H⁺] = (7.75×10⁻¹² [H⁺] + 1×10⁻¹⁴) / [H⁺]
This is quadratic equation: [H⁺]² - 7.75×10⁻¹² [H⁺] - 1×10⁻¹⁴
a = 1 ; b = - 7.75×10⁻¹² ; c = -1×10⁻¹⁴
(-b +- √(b² - 4ac) / (2a)
[H⁺] = 1.000038751×10⁻⁷
- log [H⁺] = pH → 6.999
A very strong acid as HBr, in this case, it is so diluted that its pH is almost neutral.
Good ventilation as a product of it is pure Cl2 gas
Answer:hope we can be friends
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Although phlorizin inhibition of Na+-glucose cotransport occurs within a few seconds, 3H-phlorizin binding to the sodium-coupled glucose transport protein(s) requires several minutes to reach equilibrium (the fast-acting slow-binding paradigm). Using kinetic models of arbitrary dimension that can be reduced to a two-state diagram according to Cha’s formalism, we show that three basic mechanisms of inhibitor binding can be identified whereby the inhibitor binding step either (A) represents, (B) precedes, or (C) follows the rate-limiting step in a binding reaction. We demonstrate that each of mechanisms A–C is associated with a set of unique kinetic properties, and that the time scale over which one may expect to observe mechanism C is conditioned by the turnover number of the catalytic cycle. In contrast, mechanisms A and B may be relevant to either fast-acting or slow-binding inhibitors.
Explanation:
Answer:
Ge
Explanation:
pretty sure im on high school 12th
Answer:
Br
Explanation:
Given data:
Mass of gas = 0.239 g
Volume of gas = 100 mL
Pressure exerted by gas = 603 mmHg
Temperature of gas = 14 °C
What is gas = ?
Solution:
Volume of gas = 100 mL (100mL ×1 L/1000 mL= 0.1 L)
Pressure exerted by gas = 603 mmHg (603/760 = 0.79 atm)
Temperature of gas = 14°C ( 14+273 = 287 K)
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
now we will calculate the number of moles.
n = PV/RT
n = 0.79 atm × 0.1 L / 0.0821 atm.L/ mol.K × 287 K
n = 0.079 /23.563 /mol
n = 0.003 mol
Molar mass of gas:
Number of moles = mass/molar mass
0.003 mol = 0.239 g/ molar mass
Molar mass = 0.239 g/ 0.003 mol
Molar mass = 79.7 g/mol
The molar mas of Br is 79.9 g/mol so it is closer to 79.7 thus given gas is Br.