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Ulleksa [173]
2 years ago
10

Citric acid (C6H8O7) is a triprotic acid (It has 3 protons that can dissociate when dissolved) found naturally in lemon juice, a

nd it is widely used as a flavoring in beverages. What is the molarity of C6H8O7 in commercially available lemon juice if 14.26 mL of 1.751 M NaOH is required in a titration to neutralize 20.00 mL of the juice
Chemistry
1 answer:
Gnesinka [82]2 years ago
4 0

<u>Answer:</u> The molarity of citric acid that is commercially available lemon juice is 0.416 M

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is C_6H_8O_7

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=3\\M_1=?M\\V_1=20.00mL\\n_2=1\\M_2=1.751M\\V_2=14.26mL

Putting values in above equation, we get:

3\times M_1\times 20.00=1\times 1.751\times 14.26\\\\M_1=\frac{1\times 1.751\times 14.26}{3\times 20.00}=0.416M

Hence, the molarity of citric acid that is commercially available lemon juice is 0.416 M

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There are two subshells that are s and p, which are present in the second energy level.

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4 0
1 year ago
A balloon has a volume of 3.0 L at room temperature (27oC). At what temperature would the balloon have a volume of 4.0L?
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Answer: 400K

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Given that,

Original volume of balloon V1 = 3.0L

Original temperature of balloonT1 = 27°C

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(27°C + 273 = 300K)

New volume of balloon V2 = 4.0L

New temperature of balloon T2 = ?

Since volume and temperature are given while pressure is constant, apply the formula for Charle's law

V1/T1 = V2/T2

3.0L/300K = 4.0L/T2

To get the value of T2, cross multiply

3.0L x T2 = 4.0L x 300K

3.0LT2 = 1200LK

Divide both sides by 3.0L

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Thus, at a temperature of 400 Kelvin, the balloon would have a volume of 4.0L.

6 0
3 years ago
A sealed container at 25oC contains a gas at a pressure of 104 kPa. What is the pressure of the gas when it is heated to 225oC?
seropon [69]

Answer:

174 kPa

Explanation:

Given that,

Initial temperature, T₁ = 25° C = 25+273 = 298 K

Final temperature, T₂ = 225°C = 225 + 273 = 498 K

Initial pressure, P₁ = 104 kPa

We need to find the new pressure. The relation between the temperature and pressure is given by :

\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}

So,

P_2=\dfrac{P_1T_2}{T_1}\\\\P_2=\dfrac{104\times 498}{298}\\\\P_2=173.79\ kPa

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