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3 years ago

How many moles are there in 132g of CO2

1 answer:

8 0

You can use grams to moles and moles to grams. In your case just grams to moles. So since you're given grams, you would divide that by the molar mass of CO2 because that's how many grams are in one mole. The mass for Carbon is 12.0104 g/mol and Oxygen it's 15.9994 g/mol so to find the molar mass you would add 12.0104 + (2*15.9994) which gives you a molar mass of 44.0095 g/mol. You divide your given mass (132g) by the molar mass, so there's 2.9993 moles or approximately 3 moles in 132 g of CO2.

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Suppose that Daniel has a 3.00 3.00 L bottle that contains a mixture of O 2 O2 , N 2 N2 , and CO 2 CO2 under a total pressure of

Alenkinab [10]

Answer:

Partial pressure O₂ → 2.74 atm

Explanation:

Let's analyse the data given:

Volume → 3L

In the bottle there is a mixture of gases that contains, O₂, N₂ and CO₂.

Total pressure is 4.80 atm

Let's apply the Ideal Gases Law to determine the total moles of the mixture

P . V = n . R. T

4.80 atm . 3L = n . 0.082 . 273K

n = 4.80 atm . 3L / 0.082 . 273K → 0.643 moles

We apply the concept of mole fraction:

Mole fraction of a gas X = moles of gas X / Total moles

Mole fraction of a gas X = Partial pressure X / Total pressure

In a mixture, sum of mole fraction of each gas = 1

We determine mole fraction of N₂ → 0.230 / 0.643 = 0.357

We determine mole fraction of CO₂ → 0.350 atm / 4.80 atm = 0.0729

1 - mole fraction N₂ - mole fraction CO₂ = mole fraction O₂

1 - 0.357 - 0.0729 = 0.5701 → mole fraction O₂

We replace in the formula: Mole fraction O₂ = Partial pressure O₂ / 4.80 atm

0.5701 . 4.80 atm = Partial pressure O₂ → 2.74 atm

5 0

3 years ago

Read 2 more answers

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ss7ja [257]

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topjm [15]

Answer:

1.94

Explanation:

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3 years ago

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slamgirl [31]

Answer:

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3 years ago