An object carries a +15.5 µC charge. It is 0.525 m from a -7.25 µC charge. What is the magnitude of the electric force on the ob
1 answer:
Answer:
the force of attraction between the two charges is 3.55 N.
Explanation:
Given;
first charge carried by the object, q₁ = 15.5 µC
second charge carried by the q₂ = -7.25 µC
distance between the two charges, r = 0.525 m
The force of attraction between the two charges is calculated as;
Therefore, the force of attraction between the two charges is 3.55 N.
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Answer:
Option A
Explanation:
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Final Momentum
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Generally the equation for momentum for Ball B is mathematically given by
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Option A
Answer:
Therefore,
The magnitude of the force per unit length that one wire exerts on the other is
Explanation:
Given:
Two long, parallel wires separated by a distance,
d = 3.50 cm = 0.035 meter
Currents,
To Find:
Magnitude of the force per unit length that one wire exerts on the other,
Solution:
Magnitude of the force per unit length on each of @ parallel wires seperated by the distance d and carrying currents I₁ and I₂ is given by,
where,
Substituting the values we get
Therefore,
The magnitude of the force per unit length that one wire exerts on the other is