- <em>m</em><em>ahalaga ito upang mas mapaliwanag mo ng maayos at klaro ang isang bagay o pangyayari.</em>
<em>sana </em><em>makatulong</em><em> </em><em>hehe</em>
Answer:
Part A:
to two significant figures
Part B:
to two significant figures
Part C:
to two significant figures
Explanation:
Given that :
mass of the hydrogen = 0.30 g
the molar mass of hydrogen gas molecule = 2 g/mol
we all know that:
number of moles = mass/molar mass
number of moles = 0.30 g /2 g/mol
number of moles = 0.15 mol
For low temperature between the range of 50 K to 100 K, the specific heat at constant volume for a diatomic gas molecule = 
For Part A:




to two significant figures
Part B. For hot temperature, 




to two significant figures
Part C. For an extremely hot temperature, 




to two significant figures
Answer:
c and d
Explanation:
obviously kksxsxksxkskxkskxksxksxsxsxsxsxsxsxs
<span>equal and acting on different objects</span>