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3 years ago

hi :) is it true that zero acceleration means the object can be moving at constant velocity or at rest?

Physics

2 answers:

nirvana33 [79]3 years ago

7 0

Answer:

Explanation:

Please let me know if my answer is correct

Naya [18.7K]3 years ago

6 0

It means it can’t be moving if it had 0 acceleration

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Two very long uniform lines of charge are parallel and are separated by 0.300 m. each line of charge has charge per unit length

Alenkasestr [34]

linear charge density of system of two line charges is given as

$\lambda = 5.20 \muC/m$

now as we know that electric field due to a line charge at some distance from it is given by

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

so here we will first find the electric field of first line charge at the position of other line charge

$E = \frac{5.20 * 10^{-6}}{2 \pi * 8.85 * 10^{-12}* 0.300}$

$E = 312000 N/C$

now as we know that

$F = qE$

here q = charge on the line charge system at which force is required

E = electric field on that system of charge where force is required

now we can find the charge by

$q = \lambda * L$

$q = 5.20 * 10^{-6}* 0.05 = 0.26 * 10^{-6} C$

Now using the above formula

$F = qE$

$F = 0.26 * 10^{-6} * 312000$

$F = 0.0811 N$

so force on the part of wire is F = 0.0811 N

8 0

3 years ago

Brainliest for correct answer :)

Novosadov [1.4K]

Answer:

Explanation:

The answer is b that is the final speed - initial speed divided by the time taken

Please mark as brainliest

6 0

3 years ago

Read 2 more answers

PLEASE HELP WILL GIVE BRAINLEST!!!

Aleks04 [339]

Answer:

huh what do u want tho its nothing bad

Explanation:

3 0

3 years ago

Physics !!!!!!!!!!!!!!!!!

madreJ [45]

Answer:

1) v = -0.89 m/s

2) v = 36.5 m/s

Explanation:

1) Given

The mass of the boy, M = 45 Kg

The mass of the skateboard, m = 2 Kg

The initial velocity of the boy and skateboard is zero

According to the law of conservation of linear momentum

MV + mv = 0

V = - mv/M

Substituting the given values in the above equation

V = -2 x 20/ 45

= -0.89 m/s

Hence, the velocity of the boy, v = -0.89 m/s

2) Given

The mass of the boy, M = 47 Kg

The mass of the skateboard, m = 8 Kg

The initial combined velocity of the boy and skateboard, u = 4.2 m/s

The boy jumped off from the skateboard with velocity, V = -1.3 m/s

According to the law of conservation of momentum,

MV + mv = (M + m)u

v = [(M + m)u - MV] / m

Substituting the given values,

v = [(47 + 8)4.2 - 47(-1.3)] / 8

= 36.5 m/s

Hence, the velocity of the skateboard, v = 36.5 m/s

3 0

4 years ago

An Aichi D3A bomber, with mass of 3600 kg, departs from its aircraft carrier with a velocity of 85 m/s due east. What is the pla

Nataliya [291]

Answer:

306000 is the answer.......

7 0

3 years ago