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Sergio [31]
3 years ago
9

Calculate the change in the kinetic energy (KE) of the bottle when the mass is increased. Use the formula KE = mv2, where m is t

he mass and v is the speed (velocity). Assume that the speed of the soda bottle falling from a height of 0.8 m will be 4 m/s, and use this speed for each calculation. Record your calculations in Table A of your Student Guide. When the mass of the bottle is 0.125 kg, the KE is kg m2/s2. When the mass of the bottle is 0.250 kg, the KE is kg m2/s2. When the mass of the bottle is 0.375 kg, the KE is kg m2/s2. When the mass of the bottle is 0.500 kg, the KE is kg m2/s2.
Physics
2 answers:
DerKrebs [107]3 years ago
9 0

Answer:

1,2,3,4 on edg

Explanation:

Aliun [14]3 years ago
6 0

kinetic energy is given as

KE = (0.5) m v²

given that : v = speed of the bottle in each case =  4 m/s

when m = 0.125 kg

KE = (0.5) m v² =  (0.5) (0.125) (4)² = 1 J

when m = 0.250 kg

KE = (0.5) m v² =  (0.5) (0.250) (4)² = 2 J

when m = 0.375 kg

KE = (0.5) m v² =  (0.5) (0.375) (4)² = 3 J

when m = 0.0.500 kg

KE = (0.5) m v² =  (0.5) (0.500) (4)² = 4 J

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Kinetic energy lost in collision is 10 J.

<u>Explanation:</u>

Given,

Mass, m_{1} = 4 kg

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During collision, momentum is conserved.

Before collision, the kinetic energy is

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By plugging in the values we get,

KE = \frac{1}{2} * 4 * (5)^2 + \frac{1}{2} * 1 * (0)^2\\\\KE = \frac{1}{2} * 4 * 25 + 0\\\\

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Kinetic energy after collision:

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KE = 40J + KE(lost)

Since,

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K×E(lost) = 50 J - 40 J

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