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vredina [299]
3 years ago
6

What are like terms for 28?

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
4 0

Answer:

all the constants

Step-by-step explanation:

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At a certain hospital 39080 patients had their falls reported in the winter of 2004, thisrose to 42045 patients in the winter of
Natali [406]
Answer:

Percentage rise in patients from 2004 to 2014 = 7.59%

Explanation:

The number of patients in 2004 = 39080

The number of patients in 2014 = 42045

Increase in the number of patients = (The number of patients in 2014) - (The number of patients in 2004)

Rise in the number of patients = 42045 - 39080

Rise in the number of patients = 2965

\begin{gathered} \text{Percentage rise in patients = }\frac{\text{Rise in the number of patients}}{\text{Number of patients in 2004}}\times100 \\ Percentage\text{ rise in patients = }\frac{2965}{39080}\times100 \\ \text{Percentage rise in patients = }7.59\text{ \%} \end{gathered}

Percentage rise in patients from 2004 to 2014 = 7.59%

4 0
1 year ago
How much gift wrap is needed to cover a box which measures 3 feet by 2 feet by 3 feet?
ankoles [38]
Can you help me with something?
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3 years ago
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Find the perimeter of the figure. round all figures to the nearest hundredth Place
Talja [164]
13-9 = 4ft
4/2 = 2ft
2^2+4^2=20
Length of the sides: √20 or 4.47ft
13+9+4.47+4.47 = 30.94ft
The answer is C
6 0
3 years ago
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The given line segment has a midpoint at (3, 1). What is the equation, in slope-intercept form, of the perpendicular bisector of
viva [34]

Answer:

Step-by-step explanation:

I think the attached photo supports for your question

Here is my anser:

We need to find the slope of the of and from the graph, we see that if x increases from 2 to 4, y decreases from 4 to -2.  Thus, the slope of the blue line is : \frac{-2-4}{4-2} = -3

But the slope of the perpend. bisector of the blue line is the negative reciprocal of -3, or  m= 1/3.

Let's find the slope-intercept form of this bisector.  We need to determine b in y=mx+b.  Referring to the midpoint of the blue line, x= 3; y= 1; and m=1/3.  Then

y=mx+b becomes 1=(1/3)(3) + b.  Solving for b:  1=1+b.  Then b=0.

Thus, the equation of the perpendicular bisector of the blue line through (3,1) is  y=mx + b, or y=(1/3)x + 0, or y=x/3.

9 0
3 years ago
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Given: MQ = NQ; Q is the midpoint of LP; LM ≅ PN Which congruence theorem can be used to prove △MLQ ≅ △NPQ? AAS SSS ASA SAS
masya89 [10]
The answer is SSS. Just took the test
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3 years ago
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