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s344n2d4d5 [400]
3 years ago
13

Nitrogen dioxide decomposes to nitric oxide and oxygen via the reaction: 2NO2 → 2NO + O2 In a particular experiment at 300 °C, [

NO2] drops from 0.0100 to 0.00650 M in 100 s. The rate of disappearance of NO2 for this period is __________.
Chemistry
1 answer:
Setler [38]3 years ago
3 0

Answer:

rate=-1.75x10^{-5}\frac{M}{s}

Explanation:

Hello,

In this case, for the given information, we can compute the rate of disappearance of NO₂ by using the following rate relationship:

rate=\frac{1}{2}*\frac{C_f-C_0}{t_f-t_0}

Whereas it is multiplied by the the inverse of the stoichiometric coefficient of NO₂ in the reaction that is 2. Moreover, the subscript <em>f</em> is referred to the final condition and the subscript <em>0</em> to the initial condition, thus, we obtain:

rate=\frac{1}{2}*\frac{0.00650M-0.0100M}{100s-0s}\\\\rate=-1.75x10^{-5}\frac{M}{s}

Clearly, it turns out negative since the concentration is diminishing due to its consumption.

Regards.

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The formula used for relative saturation is:

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Now put all the given values in the above formula, we get:

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Now we have to calculate the molar saturation.

The formula used for molar saturation is:

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P(vapor free) = 100 kPa - 8 kPa = 92 kPa

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\text{Molar saturation}=\frac{P_{vapor}}{P_{\text{vapor free}}}

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