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slava [35]
2 years ago
14

Help me plzzz I need answers

Physics
1 answer:
soldier1979 [14.2K]2 years ago
4 0

Answer:

i think it is B

Explanation:

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Which statement is not a good practice when working inside a computer case?
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a. be sure to hold expansion cards by the edge connectors

Explanation:

Removal of loose jewelry is a good safety practice. Also not touching a microchip with a magnetized screwdriver is also a good practice.

But holding expansion cards by the edge connectors is not a good practice, so it is the odd one in the question. Therefore answer option a provides the correct and best answer to the question

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Six parts of Health-Related Fitness
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Explain the term "avalanche state"
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Answer:

The downwind side of an obstacle such as a ridge. The addition of weight on top of a snowpack, usually from precipitation, wind drifting, or a person. An avalanche that releases from a point and spreads downhill collecting more snow - different from a slab avalanche. Also called a point-release or sluff.

Explanation:

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3 years ago
A gray kangaroo can bound across level ground with each jump carrying it 9.6 m from the takeoff point. Typically the kangaroo le
xz_007 [3.2K]

Answer:

(A) 11 m/s

(B) 1.3 m

Explanation:

Horizontal range, R = 9.6 m

Angle of projection, theta = 28 degree

(A)

Use the formula of horizontal range

R = u^2 Sin 2 theta / g

u^2 = R g / Sin 2 theta

u^2 = 9.6 × 9.8 / Sin ( 2 × 28)

u = 10.65 m/s

u = 11 m/s

(B)

Use the formula for maximum height

H = u^2 Sin ^2 theta / 2g

H =

10.65 × 10.65 × Sin^2 (28) / ( 2 × 9.8)

H = 1.275 m

H = 1 .3 m

4 0
2 years ago
You are explaining to friends why astronauts feel weightless orbiting in the space shuttle, and they respond that they thought g
bezimeni [28]

Answer:

It's only 1.11 m/s2 weaker at 400 km above surface of Earth

Explanation:

Let Earth radius be 6371 km, or 6371000 m. At 400km above the Earth surface would be 6371 + 400 = 6771 km, or 6771000 m

We can use Newton's gravitational law to calculate difference in gravitational acceleration between point A (Earth surface) and point B (400km above Earth surface):

g = G\frac{M}{r^2}

where G is the gravitational constant, M is the mass of Earth and r is the distance form the center of Earth to the object

\frac{g_B}{g_A} = \frac{GM/r^2_B}{GM/r^2_A}

\frac{g_B}{g_A} = \left(\frac{r_A}{r_B}\right)^2

\frac{g_B}{g_A} = \left(\frac{6371000}{6771000}\right)^2

\frac{g_B}{g_A} = 0.94^2 = 0.885

g_B = 0.885 g_A

So the gravitational acceleration at 400km above surface is only 0.885 the gravitational energy at the surface, or 0.885*9.81 = 8.7 m/s2, a difference of (9.81 - 8.7) = 1.11 m/s2.

6 0
3 years ago
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