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djverab [1.8K]
3 years ago
5

At which concentration of glucose carriers was the glucose concentration reduced to zero?

Chemistry
1 answer:
Agata [3.3K]3 years ago
8 0
Had to look for the options and here is the answer. The concentration of glucose carriers in which the glucose concentration is being decreased to zero is 400. This level is already classified as above normal of the rate of glucose concentration. Hope this helps.
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Theoretically, how many moles of carbonic acid will be produced by 3.00 g sample of NaHCO3?
Kryger [21]
NaHCO3 = 22.99 + 1.008 + 16(3) = 83.99 g/mol 

Na = 22.99g/83.99 g weight of molecule =.2727 or 27.27% 

3.0 g* .2727 = 0.8211 grams of sodium in sample of NaHCO3 

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17. Physical properties of a material include all but ________________.
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Answer:

17)c: the reactivity of a metal.

Explanation:

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4 0
3 years ago
_AI + _HCI —> _H2 + _AlCl3
SOVA2 [1]

Hey there!

Al + HCl → H₂ + AlCl₃

Balance Cl.

1 on the left, 3 on the right. Add a coefficient of 3 in front of HCl.

Al + 3HCl → H₂ + AlCl₃

Balance H.

3 on the left, 2 on the right. We have to start by multiplying everything else by 2.

2Al + 3HCl → 2H₂ + 2AlCl₃

Now we have 2 on the right and 4 on the left. Change the coefficient in front of HCl from 3 to 4.

2Al + 4HCl → 2H₂ + 2AlCl₃

Now, for Cl, we have 4 on the left and 6 on the right. Change the coefficient in front of HCl again from 4 to 6.

2Al + 6HCl → 2H₂ + 2AlCl₃

Now, our H is unbalanced again. 6 on the left, 4 on the right. Change the coefficient in front of H₂ from 2 to 3.

2Al + 6HCl → 3H₂ + 2AlCl₃  

Balance Al.

2 on the left, 2 on the right. Already balanced.

Here is our final balanced equation:

2Al + 6HCl → 3H₂ + 2AlCl₃  

Hope this helps!

7 0
3 years ago
Write the formula and determine the percent by mass of the salt in barium hydroxide octahydrate *
user100 [1]

Answer:

315.51g/mol

Explanation:

137(33 + (16.00 + 1.01) 2 + 8 [1.01 (2) + 16.00] = 315.51g/mol

7 0
2 years ago
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