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Sedaia [141]
3 years ago
14

Suppose 'A' is a liquid aromatic compound with molecular weight 78 and burns with sooty flame. a.Give the name of the compound '

A' b.write the molecular structure of 'A' C. What is the product when 'A' is treated with ? i.conc.HNO3 with conc.H2SO4 as catalyst ii.Halogen (cl2)in presence of sunlight and mention the use of the product obtained​
Chemistry
1 answer:
Oliga [24]3 years ago
3 0

Aromatic compounds are compounds that contain carbon-carbon multiple bonds.

The question did not mention that a heteroatom is present in the compound so we can assume that there is none of such. In that case, the compound contains only hydrogen and carbon.

So,

(CH)n = 78

where n is the number of each atom present.

(12 +1)n = 78

n = 78/13

n = 6

The molecular formula of the compound is C6H6

When C6H6 is treated with .conc.HNO3/conc.H2SO4 the compound shown in image 1 is formed. The reaction occurs at the C-C multiple bond.

When C6H6 is reacted with chlorine in the presence of sunlight, hexachlorobenzene (shown in image 2 attached) is formed.

brainly.com/question/24305135

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WHICH IS NOT A PROPERTY OF GOLD?
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Explanation:

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8 0
4 years ago
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The equilibrium constant kp at 427°c for the reaction n 2( g) 3h 2( g) 2nh 3( g) is 9. 4 × 10 –5. what is δ g° for the reaction
SashulF [63]

ΔG° for the reaction is 5.47kJ mol⁻¹.

The energy that a substance has available for utilization in a chemical reaction or transformation is known as the Gibbs free energy. Things frequently change into other things that have less Gibbs free energy. The Gibbs free energy change indicates whether a chemical reaction will take place spontaneously or not.

By using the formula;

ΔG° = −RTlnKp

Where,

R = 8.3Jk⁻¹mol⁻¹

T = Temperature = 427 + 273 = 700 K

Kp = 8×10⁻⁵(given)

Substituting the value, we get,

ΔG° = −8.3 × 700 × ln(23×10⁻⁵)

ΔG° = −8.3 × 700 × (ln(2³)+ln 10⁻⁵)

       =  - 8.3 × 700 × (ln(2³)+ln 10⁻⁵)

       = − 8.3 × 700 × (2.07−11.5)

       =5.47×10⁴Jmol¹

       =5.47kJ mol⁻¹

Therefore,  ΔG° for the reaction is 5.47kJ mol⁻¹.

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7 0
2 years ago
Which one of the following reactions IS NOT balanced? 1. 2 KNO3 + 10 K → 5 K2O + N2 2. 2 SO2 + O2 → 2 SO3 3. SF4 + 3 H2O → H2SO3
Delicious77 [7]

Answer:

2 KNO₃ + 10 K → 5 K₂O + N₂  (option 1)

Explanation:

1. 2 KNO₃ + 10 K → 5 K₂O + N₂

We have in reactant side:

2 K, 2N, 6O and 10 K. In conclussion, 12 K, 2N and 6 O

We have in product side.

10 K, 5O and 2 N

This equation is unbalanced

2. 2 SO₂ + O₂ → 2 SO₃

In reactant side we have 2 S and 6 O

In product side we have 2 S and 6 O

3. SF₄ + 3 H₂O → H₂SO₃ + 4 HF

In reactant side we have 1 S, 4F, 6 H and 3 O

In product side we have 1 S, 4F, 6 H and 3 O

6 0
3 years ago
Write the chemical formula for:
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Lead (IV) nitrate + sodium sulfate lead(IV) sulfate + sodium nitrate
 Pb(NO3)4 (aq) + 2 Na2SO4 (aq) Pb(SO4)2 (s) + 4 NaNO3 (aq)
I think this is what you are looking for. If not I am sorry.
6 0
3 years ago
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