Suppose 'A' is a liquid aromatic compound with molecular weight 78 and burns with sooty flame. a.Give the name of the compound '
1 answer:
Aromatic compounds are compounds that contain carbon-carbon multiple bonds.
The question did not mention that a heteroatom is present in the compound so we can assume that there is none of such. In that case, the compound contains only hydrogen and carbon.
So,
(CH)n = 78
where n is the number of each atom present.
(12 +1)n = 78
n = 78/13
n = 6
The molecular formula of the compound is C6H6
When C6H6 is treated with .conc.HNO3/conc.H2SO4 the compound shown in image 1 is formed. The reaction occurs at the C-C multiple bond.
When C6H6 is reacted with chlorine in the presence of sunlight, hexachlorobenzene (shown in image 2 attached) is formed.
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Answer:
Explanation:
Given that:
From equation (3) , multiplying (-1) with equation (3) and interchanging reactant with the product side; we have:
Multiplying (2) with equation (4) ; we have:
From equation (1) ; multiplying (-1) with equation (1); we have:
From equation (2); multiplying (3) with equation (2); we have:
Now; Adding up equation (5), (6) & (7) ; we get:
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(According to Hess Law)