To answe this question, we will assume that the percentage abundance of 14n is y. Since the percentage abundance of 14n + percentage abundance of 15n = 100% = 1
Therefore, percentage abundance of 15n = 1 - y.
Now we know that the average atomic mass of nitrogen is 14.0067
Therefore:
average atomic mass of nitrogen = atomic mass of 14n x its percentage abundance + atomic mass of 14n x its percentage abundance
14.0067 = 14.003074002 y + <span>15.00010897 (1 - y)
</span>14.0067 = 14.003074002 y + 15.00010897 - 15.00010897 y
14.0067 - 15.00010897 = 14.003074002 y - 15.00010897 y
<span>0.99703497 y = 0.99340897
</span>
Therefore y = <span> 0.99636
Based on this, the percentage abundance of 14n is </span> 0.99636x100= <span>99.636%
while percentage abundance of 15n = 100% - </span>99.636% = <span>0.364%</span>
Definition-A formation of new chemical substances.
Example- Sugar undergoes a chemical change when it is cooked to make caramel. :3
Hope I helped! Sorry if it's bad.
Answer:
4,5-Dimethylhex-2-ene is the least substituted alkene, so it is the least stable and gives the highest heat of hydrogenation.
Explanation:
brainiest plz
There are 3.2664292991356043 moles of MgCl2
Answer: option C) II < III < I
i.e [OH−] < [H3O+] < I
Explanation:
First, obtain the pH value of I and II, then compare both with III.
For I
Recall that pH = -log (H+)
So pH3O = -log (H3O+)
= - log (1x10−5)
= 4
For II
pOH = - log(OH-)
= - log(1x10−10)
= 9
For III
pH = 6
Since, pH range from 1 to 14, with values below 7 to be acidic, 7 to be neutral, above 7 to be alkaline: then, 9 < 6 < 4
Thus, the following solutions from least acidic to most acidic is II < III < I
