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san4es73 [151]
3 years ago
15

Use the following vocabulary words in a 3-5 paragraph sentence. Please highlight or bold the words as you use them in your parag

raph.
"carbohydrate, chemical formula, dehydration synthesis, disaccharide, glucose, hydrolysis, monosaccharide, polysaccharide, valence"
Chemistry
1 answer:
kaheart [24]3 years ago
3 0

Answer:

hey baby leave all and come with me

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Helium has a density of 1.79 x 10-4 g/mL at standard temperature and pressure. A balloon has a volume of 6.3 liters. Calculate t
LenaWriter [7]
The density of He is 1.79 x 10⁻⁴ g/mL
In other words in 1 mL there's 1.79 x 10⁻⁴ g of He. 
To fill a volume of 6.3 L the mass of He required 
    = 1.79 x 10⁻⁴ g/mL * 6300 mL
   = 11 277 * 10⁻⁴ g
  Therefore mass of He required = 1.1277 g of He
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3 years ago
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What terms refers to the process by which astronomers study distant objects by dissecting examining the spectrum of light an obj
mart [117]
Spectroscopy because it talks about the study of spectrum of light.
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3 years ago
Dr. Terror has developed a new alloy called Ultranomium. He is testing a bar that is 1.25 m1.25 m long and has a mass of 382 g.3
MrRissso [65]

Answer:0.8742j/g°C

Explanation: SOLUTION

GIVEN

length of bar=1.25m

mass 382g

temperature= 20°C to 288°C

Q=89300J

Specific Heat Capacity  will be calculated using

Q=mC∆T

where

C = specific heat capacity

Q = heat

m = mass

Δ T = change in temperature

C=Q/ m∆T

=89300/382X(288-20.6)

=0.8742j/g°C

4 0
3 years ago
Do nonmetals form anions or cations?
MrRa [10]
Since medals form cations
nonmedals form anions
8 0
3 years ago
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If 10.62 mL of a standard 0.3330 M KOH solution reacts with 98.20 mL of CH3COOH solution, what is the molarity of the acid solut
Nikolay [14]

Answer:

0.036 M of CH_{3} COOH

Explanation:

It is an example of acid-base neutralization reaction.

KOH  + CH_{3} COOH  ----> CH_{3} COO^{-} K^{+}   +   H_{2}O

Base           Acid                           Salt                                    

When two component react then the number of moles of both the component should be same, therefore the number of moles and acids and bases should be the same in the following .

Molarity= \frac{\textrm{No. of Moles}}{\textrm{Volume of the Particular Solution}}

No.of moles= Molarity × Volume of the Particular Solution

Therefore,

M_{1}V_{1} =M_{2}V_{2}------------------------------(1)

where

M_{1}= Molarity of Acid

V_{1}= Volume of Acid

M_{2}= Molarity of Base

V_{2}= Volume of Base

M_{1}=0.3330 M

V_{1}=10.62 mL

V_{2}=98.2 mL

M_{2}=??(in M)

Plugging in Equation 1,

0.3330 × 10.62 =M_{2}  × 98.2  

M_{2}=\frac{0.3330*10.62}{98.2}

M_{2}=0.036 M

3 0
3 years ago
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