The density of He is 1.79 x 10⁻⁴ g/mL
In other words in 1 mL there's 1.79 x 10⁻⁴ g of He.
To fill a volume of 6.3 L the mass of He required
= 1.79 x 10⁻⁴ g/mL * 6300 mL
= 11 277 * 10⁻⁴ g
Therefore mass of He required = 1.1277 g of He
Spectroscopy because it talks about the study of spectrum of light.
Answer:0.8742j/g°C
Explanation: SOLUTION
GIVEN
length of bar=1.25m
mass 382g
temperature= 20°C to 288°C
Q=89300J
Specific Heat Capacity will be calculated using
Q=mC∆T
where
C = specific heat capacity
Q = heat
m = mass
Δ T = change in temperature
C=Q/ m∆T
=89300/382X(288-20.6)
=0.8742j/g°C
Since medals form cations
nonmedals form anions
Answer:
0.036 M of 
Explanation:
It is an example of acid-base neutralization reaction.
KOH +
---->
+ 
Base Acid Salt
When two component react then the number of moles of both the component should be same, therefore the number of moles and acids and bases should be the same in the following .
Molarity= 
No.of moles= Molarity × Volume of the Particular Solution
Therefore,
------------------------------(1)
where
= Molarity of Acid
= Volume of Acid
= Molarity of Base
= Volume of Base
=0.3330 M
=10.62 mL
=98.2 mL
=??(in M)
Plugging in Equation 1,
0.3330 × 10.62 =
× 98.2
=
=0.036 M