Long chains of carbon molecules.
Answer:
Explanation:
Hello,
In this case, we can write the following relationship, explaining that the lost by the hot water is gained by the cold water:
Which in terms of mass, specific heat and temperatures, we have:
Whereas the specific heat of water is cancelled out to obtain the following temperature, considering that the density of water is 1 kg/L:
Regards.
The number of solid precipitate that will be formed is 37.08 g
calculation
write the equation for reaction
=Hg(NO3)2 +Na2SO4 = HgSO4(s) +2NaNO3(aq)
find the moles of each reactant
moles ofHg(NO3)2=126.27/324.6= 0.389 moles
moles of Na2SO4=17.796/142=0.125 moles
NaSO4 is the limiting reagent and by use of mole ratio of NaSO4:HgSO4 which is 1:1 therefore the moles of H2SO4 is also= 0.125 moles
mass HgSO4=moles x molar mass
=0.125 x296.65= 37.08g
Answer: A) Dialogue
Explanation: You didn’t really give me anything, so the best answer I would go with is A.
