If an item takes up 1 mL of space and has a mass of 3 grams what is the density
1 answer:
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The empirical formula : C₁₂H₄F₇
The molecular formula : C₂₄H₈F₁₄
<h3>Further explanation</h3>mol C (MW=12 g/mol)
mol H(MW=1 g/mol) :
mol F(MW=19 g/mol)
mol ratio of C : H : O =1.52 : 0.51 : 0.89=3 : 1 : 1.75=12 : 4 : 7
Empirical formula : C₁₂H₄F₇
(Empirical formula)n=molecular formula
( C₁₂H₄F₇)n=562 g/mol
(12.12+4.1+7.19)n=562
(281)n=562⇒ n =2
Molecular formula : C₂₄H₈F₁₄
<u>Answer:</u> The mass of iron produced will be 77.6 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For FeO:</u>
Given mass of FeO = 125 g
Molar mass of FeO = 71.8 g/mol
Putting values in equation 1, we get:
- <u>For aluminium:</u>
Given mass of aluminium = 25.0 g
Molar mass of aluminium = 27 g/mol
Putting values in equation 1, we get:
The given chemical reaction follows:
By Stoichiometry of the reaction:
2 moles of aluminium metal reacts with 3 mole of FeO
So, 0.93 moles of aluminium metal will react with = of FeO
As, given amount of FeO is more than the required amount. So, it is considered as an excess reagent.
Thus, aluminium metal is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of aluminium metal produces 3 mole of iron metal
So, 0.93 moles of aluminium metal will produce = of iron metal
- Now, calculating the mass of iron metal from equation 1, we get:
Molar mass of iron = 55.85 g/mol
Moles of iron = 1.395 moles
Putting values in equation 1, we get:
Hence, the mass of iron produced will be 77.6 grams