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3 years ago

Please answer the question.

Chemistry

1 answer:

guajiro [1.7K]3 years ago

7 0

Answer: 28.57 L NH3

50 L O2 * 1 mol O2 / 22.4 L O2 * 4 mol NH3 / 7 mol O2 * 22.4 L NH3 / 1 mol NH3 = 28.57 L NH3

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4 years ago

What happens when a candle stops burning after putting a glass jar over them

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The candle ran out of oxygen

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3 years ago

How does Silicon shape our technological reality

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4 years ago

Read 2 more answers

Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where need

gregori [183]

Answer:

Explanation:

Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron flow arrows should start on the electron(s) of an atom or a bond and should end on an atom, bond, or location where a new bond should be created. Include all free radicals by right-clicking on an atom on the canvas and then using the Atom properties to select the monovalent radical.

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3 years ago

If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?

andre [41]

Complete question:

The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.44×10⁻⁴ s⁻¹ at a certain temperature.

If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?

Answer:

After 210 s the concentration of SO2Cl2 will be 0.121 M

Explanation:

$ln\frac{[A_t]}{[A_0]} =-kt$

where;

At is the concentration of A at a time t

A₀ is the initial concentration of A

k is rate constant = 1.44×10⁻⁴ s⁻¹

t is time

ln(At/A₀) = -( 1.44×10⁻⁴)t

ln(At/0.125) = -( 1.44×10⁻⁴)210

ln(At/0.125) = -0.03024

$\frac{A_t}{0.125} = e^{-0.03024$

At/0.125 = 0.9702

At = 0.125*0.9702

At = 0.121 M

Therefore, after 210 s the concentration of SO2Cl2 will be 0.121 M

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3 years ago