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Nookie1986 [14]
2 years ago
8

Please answer the question.

Chemistry
1 answer:
guajiro [1.7K]2 years ago
7 0
Answer: 28.57 L NH3

50 L O2 * 1 mol O2 / 22.4 L O2 * 4 mol NH3 / 7 mol O2 * 22.4 L NH3 / 1 mol NH3 = 28.57 L NH3
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a) 20^0C and 293K

b) 437K and 327.2^0F

c) -273^0C and 459.44^0F

Explanation:

Temperature of the gas is defined as the degree of hotness or coldness of a body. It is expressed in units like ^0C , ^0Fand K  

These units of temperature are inter convertible.

t^0C=(t+273)K

t^oC=\frac{5}{9}\times (t^oF-32)

K-273=\frac{5}{9}\times (^oF-32)

a)  68°F (a pleasant spring day) to °C and K.

Converting this unit of temperature into ^0C and K by using conversion factor:

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t=20^0C

20^0C=(20+273)K=293K

b) 164°C (the boiling point of methane, the main component of natural gas) to K and °F

Conversion from degree Celsius to Kelvins  and Fahrenheit

164C=\frac{5}{9}\times (t^oF-32)

t^0F=327.2

164°C=(164+273)K=437 K

c) 0K (absolute zero, theoretically the coldest possible temperature) to °C and °F.

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0-273=\frac{5}{9}\times (t^oF-32)

t=-459.4^0F

t^K=(0-273)^0C=-273^0C

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