Answer:
Only one seven carbon hydrocarbon was produced.
Explanation:
- Alkynes are reduced completely in presence of
to produce alkanes. - Hydrogenation in presence of Pt is a simple nucleophilic addition process where
molecule adds onto an unsaturated bond. - Hept-1-yne, hept-2-yne and hept-3-yne are constitutionally isomeric to each other. Hence, after complete reduction, all three alkynes produced heptane as only product.
- So, only one seven carbon hydrocarbon was produced.
Answer:
Explanation:
The products of this reaction are given by:
Firstly, dichromate anion becomes chromium(III) cation, let's write this change:
The following steps should be taken:
- balance the main element, chromium: multiply the right side by 2 to get 2 chromium species on both side:
- balance oxygen atoms by adding 7 water molecules on the right:
- balance the hydrogen atoms by adding 14 protons on the left:
- balance the charge (the total net charge on the left is 12+, on the right we have 6+, so 6 electrons are needed on the left):
Similarly, tin(II) cation becomes tin(IV) cation:
Now that we have the two half-equations, multiply the second one by 3, so that it also has 6 electrons that will be cancelled out upon addition of the two half-equations:
Add them together:
Adding the ions spectators:
Answer:
One can determine the specific heat of the metal through using the clarimeter, water, thermometer and using heat equations.
Explanation:
You can learn about heat effects and calorimetery through a simple experiment by boiling water and heating up the metal in it. Then, pour it into your calorimeter and the heat will flow from the metal to the water. The two equlibria will meet: the metal will loose heat into its surroundings (the water) and teh water will absorb the heat. The heat flow for the water is the same as it is for the metal, the only difference being is the negative sign indicating the loss of the heat of the metal.
In terms of theromdynamics, we can deteremine the heat flow for the metal becasue it would be equal to the mangnitued but opposite in direction. Thus, we can say that the specific heat of water qH2O = -qmetal.
Answer:
\large \boxed{\textbf{609 kJ}}
Explanation:
The formula for the heat absorbed is
q = mCΔT
Data:
m = 2.07 kg
T₁ = 23 °C
T₂ = 191 °C
C = 1.75 J·°C⁻¹g⁻¹
Calculations:
1. Convert kilograms to grams
2.07 kg = 2070 g
2. Calculate ΔT
ΔT = T₂ - T₁ = 191 - 23 = 168 °C
3. Calculate q
