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Artist 52 [7]
3 years ago
11

What does the word resolution mean in the sentence "By 1915, the British Roentgen Society had adopted a resolution to protect pe

ople from overexposure to X-rays"?
Physics
1 answer:
iris [78.8K]3 years ago
5 0
Resolution in this sentence refers to a solution to the problem 
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A car travels at 60 miles per hour. How much time does it take the car to travel 30 miles? Select one: a. 1 hour b. 1/2 hour c.
andreev551 [17]
The car is traveling at 60 miles per hour. Theoretically, at this pace, It'll take (B.), 1/2 an hour.


Brainliest?


Hope I helped! ^-^
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3 years ago
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What are the units of measure for distance?
olga2289 [7]
The most common unit is meters (m for short). It is the base unit for distance or displacement in the metric system. If you are dealing with larger distances, you might use kilometers (I'm for short) which is just 1000 meters. On the other hand, centimeter (cm) are used for small distances and are 1/100 of a meter. Another common unit is millimeters (mm) which is 1/1000 of a meter.
6 0
4 years ago
Emily is a competitive swimmer. Why does wearing a swim cap help Emily swim faster?
sladkih [1.3K]

Answer:

It's helps Emily became when she swims her hair is not in the way creating friction and making her swim faster. friction acts between two metals blocks that slide past each other.

Explanation:

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3 years ago
While two forces act on it, a particle of mass m=3.2kg is it to move continuously with velocity (3m/s)i - (4m/s)j . one of the f
marta [7]
Mmm tricky.
Since the velocity is constant, I'm going to assume there is no acceleration in any direction. This means there is no net force in the I or J forection!

Since there are 2 forces, both must be equal and opposite in direction to perfectly cancel each other out.

So the opposite of F1 is (-2N)I + (6N)J!

8 0
4 years ago
A clay ball (mass = 0.25kg) has a rightward momentum of +1.75 kg∙m/s. A second clay ball (mass = 0.25 kg) has a leftward momentu
julia-pushkina [17]

1)

\begin{gathered} E1=\frac{1}{2}m_1v_1^2+\frac{1}{2}m_1v_2^2 \\ where: \\ m_1=m_2=0.25kg \\ v_1=7m/s \\ v_2=-7m/s \\ so: \\ E1=\frac{1}{2}0.25(7^2)+\frac{1}{2}0.25(7^2) \\ E1=6.125+6.125 \\ E1=12.25J \end{gathered}

Answer:

d. 12.25J

------------------------

2)

According to the conservation of energy:

\begin{gathered} E1=E2 \\ so: \\ E2=12.25J \end{gathered}

Answer:

b. 12.25

-------------------------------

3)

P1=m_1v_2+m_2v_2=+1.75-1.75=0

Answer:

d. 0 kg∙m/s

-----------------------------------------

4)

Using conservation of momentum:

\begin{gathered} P1=P2 \\ so: \\ P2=0 \end{gathered}

Answer:

b. 0 kg•m/s

3 0
1 year ago
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