Answer:
I don't have any answer sorryyyy!!
Explanation:
lol say to your mom what is the answer it's good to say :)) lollllll
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Answer:
Today's classification is called Linnaean system of classification. Is is important because it is according to the data of evolutionary studies and modern data.
Explanation:
It classifies plants, animals, algae fungi , and bacteria in a specific groups. It is important because this classification is somehow verified by the genetics and molecular biology.
7 levels of Linnaean classification system.
Kingdom
/Phylum
Class
Order
Family
Genus
Specie
The chemical activity series is the arrangement of the elements descendingly according to their chemical activity for reactions like simple substitution reactions and redox reactions. Elements above hydrogen can replace hydrogen from water and acids as they are more active than hydrogen. Since cesium is more active than hydrogen, it replaces it in hydrochloric acid.
2 cesium atoms loses 2 electrons first;
2Cs --> 2Cs+ + 2e-
2 hydrogen atoms recieve the two electrons;
2H+ + 2e- --> H2
The net ionic equation is;
2Cs + 2HCl --> CsCl + H2
Answer: Some atoms of the same elements that have different atomic masses are called isotopes
Explanation:
so the atoms are the same element but different in mass. Since the isotopes have the same number of protons and electrons the isotopes have much the same chemical behavior. Since the isotopes have different numbers of neutrons the nuclear behavior differs.
Answer:
The answer to your question is 9.075 g of CO₂
Explanation:
Data
mass of C₃H₈ = 39 g
mass of O₂ = 11 g
Balanced chemical reaction
C₃H₈ + 5O₂ ⇒ 3CO₂ + 4H₂
-Calculate the molar mass of the reactants
C₃H₈ = (12 x 3) + (8 x 1) = 36 + 8 = 44 g
O₂ = (16 x 2) = 32 g
-Calculate the limiting reactant
theoretical yield C₃H₈ / O₂ = 44/5(32) = 44/ 160 = 0.275
experimental yield C₃H₈/O₂ = 39/11 = 3.5
From the previous result, we conclude that the limiting reactant is O₂ because the experimental yield was higher than the theoretical yield.
-Calculate the mass of CO₂
160 g of O₂ ----------------- 3(44) g of CO₂
11 g of O₂ ------------------ x
x = (11 x 3(44)) / 160
x = 1452 / 160
x = 9.075 g of CO₂