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Lilit [14]
3 years ago
15

The step by step experiment to determine the cubic expansivity of a liquid

Physics
1 answer:
Anit [1.1K]3 years ago
7 0
In accordance with the definition of density as r = m/V, in order to determine the density of matter, the mass and the volume of the sample must be known. The determination of mass can be performed directly using a weighing instrument. The determination of volume generally cannot be performed directly. Exceptions to this rule include · cases where the accuracy is not required to be very high, and · measurements performed on geometric bodies, such as cubes, cuboids or cylinders, the volume of which can easily be determined from dimensions such as length, height and diameter. · The volume of a liquid can be measured in a graduated cylinder or in a pipette; the volume of solids can be determined by immersing the sample in a cylinder filled with water and then measuring the rise in the water level. Because of the difficulty of determining volume with precision, especially when the sample has a highly irregular shape, a "detour" is often taken when determining the density, by making use of the Archimedean Principle, which describes the relation between forces (or masses), volumes and densities of solid samples immersed in liquid: From everyday experience, everyone is familiar with the effect that an object or body appears to be lighter than in air – just like your own body in a swimming pool. Figure 3: The force exerted by a body on a spring scale in air (left) and in water (right)
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A bungee-jumping company operates on a bridge 200 m above the ground. They use bungee cords that are 100 m when they are unstret
zubka84 [21]

Answer:

m = 63.7 kg

Explanation:

As we know that when mass connected to the bungee cord stretch the string then the gravitational potential energy of the person will convert into potential energy of the string at the end

now here we know that when person jump from the top and reach at the end then loss in gravitational potential energy is given as

U = mgH

U = m(9.81)(200)

U = 1962 m

now when it is at the end of the motion stretch in the string will be

x = 200 - 100 = 100 m

now potential energy of string is given as

U_{spring} = \frac{1}{2}kx^2

U_{spring} = \frac{1}{2}(25)(100^2)

now by energy conservation we have

1962 m = \frac{1}{2}(25)(100^2)

m = 63.7 kg

6 0
3 years ago
Why do people cry but dont say whats wrong they jus stand and act like we kno wha wrong
Finger [1]

Answer:

usually its because they dont wanna talk

Explanation:

I know what thats  like. Either that or they don't trust you. It could be something personal or they just dont wanna talk. But i wouldn't push. Just let them talk if they want to

5 0
4 years ago
How to find when the particle changes direction?
sergeinik [125]
<span>As time increases, if the particle's velocity changes sign from positive to negative, or negative to positive, then it must have changed (opposite) direction on its linear path. As time increases on a graph of the particle's position versus time, it changes directions when position changes from increasing to decreasing, or from decreasing to increasing.</span>
5 0
4 years ago
Which description best models the energy transfer that occurs in the radiative zone?
Zinaida [17]

Answer : Option D) A dropped wallet is kicked around the floor of a busy train station.

Explanation : The description that best suits the model for the energy transfer that occurs in the radiative zone is -

<h3>A dropped wallet is kicked around the floor of a busy train station.</h3>

As in the radiation zone, which is also called as radiative zone or radiative region in the layer of a star's interior where energy is primarily transported toward the exterior by means of radiative diffusion and thermal conduction. This can be correlated with the example of a dropped wallet in a busy train station as the wallet would be kicked by many people who are in a hurry to travel, this represents the radiative diffusion. So, every time the wallet is being kicked by someone the energy is getting transformed.

5 0
3 years ago
Read 2 more answers
a rock is vertically upward with a velocity of 10 m/s. calculate the maximum height it reaches and time taken to reach that heig
lina2011 [118]

Answer:

maximum height: p(t) = Vo * t - 1/2 * g * t^2

p’(t) = v(t) = 0 = Vo - g*t. So, maximum height occurs when t = Vo / g

p(Vo / g) = Vo^2/g - 1/2 * g * (Vo/g)^2

Vo = 10 m / s. Let’s approximate g = 10 m / s^2

p(Vo / g) = 10^2 / 10 - 1/2 * 10 * (10/10)^2 = 10 - 5 = 5 meters (approximately)

Calculation of time:

v = u + gt

0 = 10√2 + (-10)t

-10√2 = -10t

2 = √2s

8 0
3 years ago
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