Assume that the deceleration due to braking is a ft/s².
Note that
40 mph = (40/60)*88 = 58.667 ft/s
25 mph = (25/60)*88 = 36.667 ft/s
The final velocity is zero when the car stops, therefore
v² - 2ad = 0, or d = v²/(2a)
where
v = initial speed
a = deceleration
d = stopping distance.
The stopping distance, d₄₀, at 40 mph is
d₄₀ = 58.667²/(2a)
The stopping distance, d₂₅, at 25 mph is
d₂₅ = 36.667²/(2a)
Therefore
d₄₀/d₂₅ = 58.667²/(2a) ÷ 36.667²/(2a)
= (58.667/36.667)²
= 2.56
Answer:
The stopping distance at 40 mph is 2.56 times the stopping distance at 25 mph.
Answer: Option (C) is the correct answer.
Explanation:
When yeast is added into a bottle with water and sugar then after some time yeast becomes activated. This results in the formation of a chemical change as bubbles are formed on the surface of the mixture in the bottle.
This indicates that a gas has been released due to the chemical change.
Thus, we can conclude that most likely a chemical change has occurred because a gas was produced.
Answer:
a) Acceleration of runner is 1.33 m/s²
b) Acceleration of motorcycle is 2.85 m/s²
c) The motorcycle moves 84.21-2.94 = 81.06 m farther than the runner.
Explanation:
t = Time taken
u = Initial velocity = 0
v = Final velocity
s = Displacement
a = Acceleration
Equation of motion

Acceleration of runner is 1.33 m/s²

Acceleration of motorcycle is 2.85 m/s²

The runner moves 2.94 m

The motorcycle moves 84.21 m
The motorcycle moves 84.21-2.94 = 81.06 m farther than the runner.
The required work to hold the crate above the ground is 150 joule.
We need to know about the work done to solve this problem. The work done by an object depends on the force applied and the distance. The work is proportional to force and displacement. It can be written as
W = F . s
where W is work done, F is the force and s is displacement
From the question above, the given parameters are
F = 100 N
s = 1.5
Thus, the required work to hold the crate above the ground can be calculated
W = F . s
W = 100 . 1.5
W = 150 joule
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Answer:
334.314 (kJ)
Explanation:
1) the formula for the required energy is: Q=c*m(Bp-t), where c - 4100 J/kg*C; m - 0.9 kg; Bp - 100.6 C; t - 10 C.
2) according to the formula above:
Q=4100*0.9*(100.6-10)=41*9*906=334314 (J).