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Greeley [361]
3 years ago
14

A network administrator is setting up a web server for a small advertising office and is concerned with data availability. The a

dministrator wishes to implement disk fault tolerance using the minimum number of disks required. Which RAID level should the administrator choose?
A) RAID 0B) RAID 1
C) RAID 5
D) RAID 6
Physics
1 answer:
lianna [129]3 years ago
5 0

RAID 1 level should be  choosed by the administrator.

B) RAID 1

<u>Explanation:</u>

RAID 1 is commonly utilized with a couple of plates, however, it should be possible with additional, and would indistinguishably reflect/duplicate the information similarly over all the drives in the exhibit. RAID 1  requires at least two physical drives, as information is composed at the same time to two spots.

The drives are basically identical representations of one another, so on the off chance that one drive comes up short, the other one can dominate and give access to the information that is put away on that drive. The purpose of RAID 1 is principally for repetition, as you can totally lose a drive, yet at the same time keep awake and running off the extra drive(s).

Likewise, at least two circles are required for RAID 1 equipment usage. With programming RAID 1, rather than two physical circles, information can be reflected between volumes on a solitary plate.

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Answer:

If it was close we would die.

Explanation:

Probably has something to do with the earths original formation.

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One uniform ladder of mass 30 kg and 10 m long rests against a frictionless vertical wall and makes an angle of 60o with the flo
yuradex [85]

Answer:

   μ = 0.37

Explanation:

For this exercise we must use the translational and rotational equilibrium equations.

We set our reference system at the highest point of the ladder where it touches the vertical wall. We assume that counterclockwise rotation is positive

let's write the rotational equilibrium

           W₁  x/2 + W₂ x₂ - fr y = 0

where W₁ is the weight of the mass ladder m₁ = 30kg, W₂ is the weight of the man 700 N, let's use trigonometry to find the distances

             cos 60 = x / L

where L is the length of the ladder

              x = L cos 60

            sin 60 = y / L

           y = L sin60

the horizontal distance of man is

            cos 60 = x2 / 7.0

            x2 = 7 cos 60

we substitute

         m₁ g L cos 60/2 + W₂ 7 cos 60 - fr L sin60 = 0

         fr = (m1 g L cos 60/2 + W2 7 cos 60) / L sin 60

let's calculate

         fr = (30 9.8 10 cos 60 2 + 700 7 cos 60) / (10 sin 60)

         fr = (735 + 2450) / 8.66

         fr = 367.78 N

the friction force has the expression

         fr = μ N

write the translational equilibrium equation

         N - W₁ -W₂ = 0

         N = m₁ g + W₂

         N = 30 9.8 + 700

         N = 994 N

we clear the friction force from the eucacion

        μ = fr / N

        μ = 367.78 / 994

        μ = 0.37

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3 years ago
A force F is exerted at a distance D from the axis of rotation of a wrench and is exerted at an angle θ to the wrench (θ is the
Katyanochek1 [597]

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-f * 2R  will exert an equal opposite torque

-f * 2 = F sin theta

f = -F sin theta / 2

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A solar cooker, really a concave mirror pointed at the Sun, focuses the Sun's rays 13.8 cm in front of the mirror. Part A What i
shepuryov [24]

From the concept of optics on a curvature of a spherical mirror, the proportion for which the focal length is equivalent to half the radius of curvature is fulfilled. Mathematically this is

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Replacing with our values,

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True: All matter on earth is made up of atoms.

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True: description of an electron.

True: description of a proton

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3 years ago
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