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Law Incorporation [45]
3 years ago
11

Two cars are facing each other from opposite ends of a 500m long road. Car A begins travelling at a constant speed of 20m/s. At

the same moment, Car B begins travelling toward Car A at a constant speed of 16m/s. How far will Car A move before colliding with Car B?
Physics
1 answer:
Archy [21]3 years ago
6 0

Answer:

Correct answer:  D₁ = 277.78 m  

Explanation:

Before colliding  with car B, car A will cross the next distance:

D₁ = V₁ t  

Before colliding  with car A, car B will cross the next distance:

D₂ = V₂ t

The total distance is:

D = D₁ + D₂  => D = V₁ t + V₂ t  => D = t (V₁ + V₂) => t = D / (V₁ + V₂)

t = 500 / (20 + 16) = 500 / 36 = 13.89 seconds

D₁ =  V₁ t  = 20 · 13.89 = 277.78 m

D₁ =  277.78 m

God is with you!!!

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Igoryamba
The period T of a pendulum is given by:
T=2 \pi  \sqrt{ \frac{L}{g} }
where L is the length of the pendulum while g=9.81 m/s^2 is the gravitational acceleration.

In the pendulum of the problem, one complete vibration takes exactly 0.200 s, this means its period is T=0.200 s. Using this data, we can solve the previous formula to find L:
L=g ( \frac{T}{2\pi} )^2=(9.81 m/s^2)( \frac{0.2 s}{2 \pi} )^2=1 \cdot 10^{-3} m=1 mm
4 0
2 years ago
The efficiency of a machine is always less than 100% because part of the energy input is used to
Travka [436]

Answer:

C. Overcome Friction

Explanation:

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5 0
2 years ago
The pressure in an automobile tire depends on the temperature of the air in the tire. When the air temperature is 25°C, the pres
12345 [234]

Answer:0.0704 kg

Explanation:

Given

initial Absolute pressure(P_1)=210+101.325=311.325

T_1=25^{\circ}\approx 298 K

V=0.025 m^3

T_2=50^{\circ}\approx 323 K

as the volume remains constant therefore

\frac{P_1}{T_1}=\frac{P_2}{T_2}

\frac{311.325}{298}=\frac{P_2}{323}

P_2=337.44 KPa

therefore Gauge pressure is 337.44-101.325=236.117 KPa

Initial mass m_1=\frac{P_1V}{RT_1}=\frac{311.325\times 0.025}{0.0287\times 298}

m_1=0.91 kg

Final mass m_2=\frac{P_2V}{RT_2}=\frac{311.325\times 0.025}{0.0287\times 323}

m_2=0.839

Therefore m_1-m_2=0.91-0.839=0.0704 kg of air needs to be removed to get initial pressure back

4 0
3 years ago
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13.6) When any boat displaces a weight of water equal to its own weight, it floats.
7 0
2 years ago
Why does the sky change colors at sunset?
KiRa [710]

Atmospheric refraction is the deviation of light or other electromagnetic wave from a straight line as it passes through the atmosphere due to the variation in air density as a function of height. ... Refraction not only affects visible light rays, but all electromagnetic radiation, although in varying degrees.

So in short, the answer is D.

(My answer got deleted because it didnt explain which is dumb)

8 0
2 years ago
Read 2 more answers
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