Two cars are facing each other from opposite ends of a 500m long road. Car A begins travelling at a constant speed of 20m/s. At
1 answer:
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Answer:
Average speed will be 48.23 km/h
Explanation:
Let the distance up to hill is = d km
Speed when car goes to hill = 38 km/h
So time required
Speed when car return from hill = 66 km/h
So time required to return fro hill
Total time
Total distance = d+d =2d
So average speed
Answer:
t = 1.02 s
Explanation:
The computation of the time required is shown below:
The package speed for belt is
= 3 - 1
= 2 m/s
Moreover, the decelerative force would be acted on the block i.e u.m.g
So, the decelerative produced
= 0.2 × 9.81
= 1.962 m/s^2
And, final velocity = 0
v = u - at
here
V = 0 = final velocity
u = 2 m/s
so,
0 = 2 - 1.962 × t
t = 1.02 s
your answer would be The one in the top right corner that looks a bit like this..
