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ladessa [460]
3 years ago
10

At a certain temperature, the solubility of strontium arsenate, sr3(aso4)2, is 0.0550 g/l. what is the ksp of this salt at this

temperature?
Chemistry
1 answer:
tresset_1 [31]3 years ago
5 0
<span>The ksp of the salt is equal to the square of the molar concentration. Converting g/L to to mol/L before plugging into ksp expression. The equation is equal to 1.09 x 10-4 moles. This means there is .0590 grams over 540.8 grams per mole.</span>
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By stoichiometry and assume that:

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<span>
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6 0
1 year ago
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Use the balanced equation to solve the problem.
harkovskaia [24]

Answer:

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1 N₂ + 3 F₂ ---> 2 NF₃

2.10 moles N₂        2 moles NF₃
---------------------  x  ---------------------  =  4.20 moles NF₃
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