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2 years ago

Which components do all circuits have in common? Check all that apply.

Chemistry

2 answers:

omeli [17]2 years ago

8 0

Answer: All the circuits have energy source, wires and device that needs electrical energy in common.

Explanation: Electric circuit is a path through which electrons flow from higher potential to lower potential.

A wire is required to connect Energy source and a device that needs electrical energy to run. On the other hand, voltmeter and ammeter are the devices which are used to measure voltage and current respectively and not necessarily used in all the circuits.

Hence, the common components in an electric circuit are energy source, wires and device that needs electrical energy in common.

Natalka [10]2 years ago

5 0

energy source
wires
device that needs electrical energy

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3 years ago

A 50.0 g sample of scandium, sc, is heated by exposure to 1.50 x 10 3 j. The temperature of the sc is raised by 61.1 o

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Given mass of Scandium = 50.0 g

Increase in temperature of the metal when heated = $61.1^{0}C$

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The equation showing the relationship between heat, mass, specific heat and temperature change:

$Q = m C (deltaT)$

Where Q is heat = $1.50*10^{3}J$

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$1.50*10^{3}J$ =50.0g(C)( $61.1^{0}C$ )

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3 years ago

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3 years ago

The average atomic weight of copper, which has two naturally occurring isotopes, is 63.5. One of the isotopes has an atomic weig

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Answer: The atomic weight of the second isotope is 64.81 amu.

Explanation:

Average atomic mass of an element is defined as the sum of atomic masses of each isotope each multiplied by their natural fractional abundance

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

We are given:

Let the mass of isotope 2 be 'x'

Mass of isotope 1 = 62.9 amu

Percentage abundance of isotope 1 = 69.1 %

Fractional abundance of isotope 1 = 0.691

Mass of isotope 2 = 'x'

Percentage abundance of isotope 2 = 30.9%

Fractional abundance of isotope 2 = 0.309

Average atomic mass of copper = 63.5 amu

Putting values in equation 1, we get:

$\text{Average atomic mass of copper}=[(62.9\times 0.691)+(x\times 0.309)]$

$x=64.81amu$

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2 years ago