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allsm [11]
3 years ago
11

What is an example of convection in earths system

Chemistry
1 answer:
padilas [110]3 years ago
8 0
The pool being cooler at the deep end. Also the air closer to the roof of a house being cooler.
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How many atoms are present in 34.69 moles of Mg
shusha [124]
<span>Avogadro's number. 

1 mole of any substance, molecule or element is equal to a certain amount of atom. 

6.022 x 10^23 is the Avogradro's constant. 

Magnesium Oxide is a compound. therefore if you have 30.3 g of it (1 mol), it will have the same number of atoms. 

34.69 moles of MgO has 208.9 x 10^23 number of atoms. 

2.089 x 10^25 is also a correct answer.</span><span>
</span>
7 0
3 years ago
PLSSS HELP FAST
Aliun [14]

Note the formula

\boxed{\sf Mass\:no=No\:of\:protons+No\:of\:neutrons}

For X:-

  • No of protons:-

\\ \sf\longmapsto 19-10=9protons

  • It is Fluorine.

For Y:-

  • No of protons:-

\\ \sf\longmapsto 16-8=8protons

  • It is Oxygen.

Option D is correct

7 0
2 years ago
If the compound has a molar mass of 156 g/mol, what is its molecular formula?
oksano4ka [1.4K]
I believe that the choices for this question are:
C2H4O2, C4H8O4 CH2O, C6H12O6 C3H6O3, C6H12O6 C2H4O2, C6H12O6 
 
The answer to this based on the molar masses given is:
C2H4O2, C6H12O6 
 
To prove calculate the molar mass:
C2H4O2 = 2*12 + 4*1 + 2*16 = 60
C6H12O6 = 6*12 + 12*1 + 6*16 = 180
3 0
3 years ago
a certain country, pivate enterprises provide various goods and services But the govemment provides tree public transportation a
puteri [66]
Mixed economy. Wherever the private and public sector have an active role, they are determined to be a mixed economy.
8 0
3 years ago
Calculate the DH°rxn for the decomposition of calcium carbonate to calcium oxide and carbon dioxide. DH°f means delta or change
USPshnik [31]

Answer: +178.3 kJ

Explanation:

The chemical equation  follows:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(CaO(s))})+(1\times \Delta H^0f_{CO_2}]-[(1\times \Delta H^o_f_{(CaCO_3(s))})]

We are given:

\Delta H^o_f_{(CaO(s))}=-635.1kJ/mol\\\Delta H^o_f_{(CaCO_3(s))}=-1206.9kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_{rxn}=?

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-635.1))+(1\times (-393.5))]-[(1\times (-1206.9))]

The DH°rxn for the decomposition of calcium carbonate to calcium oxide and carbon dioxide is +178.3 kJ

5 0
3 years ago
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