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Alla [95]
3 years ago
15

A wheel is rotating at 30.0 rpm. The wheel then accelerates uniformly to 50.0 rpm in 10.0 seconds. Determine the – a) rate of an

gular acceleration in rad/s2 and –
Physics
2 answers:
Mademuasel [1]3 years ago
5 0

Answer:

The angular acceleration is 0.209\ rad/s^2

Explanation:

Given that,

Angular velocity, \omega_{i} = 30.0\ rpm

Angular velocity, \omega_{f} = 50.0\ rpm

Time t = 10.0 sec

We need to calculate the angular acceleration

Using formula of angular acceleration

\alpha=\dfrac{\Delta \omega}{\Delta t}

\alpha=\dfrac{\omega_{f}-\omega_{i}}{\Delta t}

\alpha=\dfrac{50.0-30.0}{10.0}

Now, we change the angular velocity in rad/s.

\omega=20\times\dfrac{2\pi}{60}

\omega=2.09\ rad/s

\alpha=\dfrac{2.09}{10.0}

\alpha=0.209\ rad/s^2

Hence, The angular acceleration is 0.209\ rad/s^2

givi [52]3 years ago
4 0

Answer:

The rate of angular acceleration is 0.209 rad/s²

Explanation:

the solution is in the attached Word file

Download docx
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