Charge A and charge B are 3.00 m apart, and charge A is +1.44 C and charge B is +3.10 C. Charge C is located between them at a c
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Answer:
331.28 K
Explanation:
To solve this problem, you need to know that the heat that the water at 373 K is equal to the heat that the water at 285 K gains.
First, we will asume that at the end of this process there won't be any water left in gaseous state.
The heat that the steam (H20(g)) loses is equal to the heat lost because the change of phase plus the heat lost because of the decrease in temperature:
The specific Heat c of water at 298K is 4.18 kJ/K*kg.
The latent heat cl of water is equal to 2257 kJ/kg.
The heat that the cold water gains is equal to heat necessary to increase its temperature to its final value:
Remember that in equilibrium, the final temperature of both bodies of water will be equal.
Then:
To develop this problem it is necessary to apply the concepts related to Gravitational Potential Energy.
Gravitational potential energy can be defined as
As M=m, then
Where,
m = Mass
G =Gravitational Universal Constant
R = Distance /Radius
PART A) As half its initial value is u'=2u, then
Therefore replacing we have that,
Re-arrange to find v,
Therefore the velocity when the separation has decreased to one-half its initial value is 816m/s
PART B) With a final separation distance of 2r, we have that
Therefore
Therefore the velocity when they are about to collide is