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True [87]
3 years ago
11

A man pushes a stalled car with a force of 100 N. If the acceleration of the car is 0.75 m/s 2 , what is the mass of the car?

Physics
1 answer:
shutvik [7]3 years ago
4 0
125 because f=ma so you would use 100=mx0.75
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Student C said, “I don’t agree with either model you drew. I think the Sun goes around Earth. The evidence is that you can see t
xxTIMURxx [149]

Answer:

See the explanation below

Explanation:

Student c's belief is fulfilled only for the movement of the earth with respect to the sun. But it has no validity or does not exist when it is necessary to explain other physical phenomena with respect to other satellites. For example, how would you explain the phases of the moon, if the Earth is located in the center of the Galaxy?, another serious question regarding the observations made by scientists millions of years ago, where they observed that the distances of the Earth from other planets were changing, with respect to time. If the Earth was in the center, all the planets and the sun would revolve around it preserving a constant distance (radius), at all times.

Other phenomena to explain would be the seasons on Earth, these are due to the axis of inclination of the Earth and the rotation of it around the sun.

5 0
3 years ago
A boater is floating 1060 meters down a river. The person takes 40 minutes. At what speed is the boat moving?
Mashutka [201]
26.5, I’m not sure if it’s right but 1060/40 gets that
7 0
2 years ago
Plz help asap.
stich3 [128]

Answer:

In a primary cell, two electrodes (one of copper and other of zinc) of metal atoms are used. These electrodes are dipped in an electrolyte solution that causes the metals to produce their respective positive and negative ions.

In this way, the flow of charges takes place and supply the electricity to the source.

Unlike a primary cell, a dry cell contains paste of an electrolyte instead of the solution. The contents of electrolyte paste react with each other through a chemical process and convert the chemical energy into electrical energy.

5 0
3 years ago
A hockey player is standing on his skates on a frozen pond when an opposing player, moving with a uniform speed of 4.0 m/s, skat
Cerrena [4.2K]

Answer:

a)t=59.817652833125294s \approx 59.8s

b)D_1=894.01m

Explanation:

From the question we are told that

Speed of opposing player V_2=4.0m/s

First player chase his opponent aftert=2.80t

Acceleration of  first player a=0.14 m/s2

Let time of catch be  t_c

a)Generally the Equation for distance covered is mathematically given as follows

Distance to catch First opponent

D_1=\frac{1}{2}(0.14)t^2

D_1=0.07t^2

Distance to covered Second opponent

D_2=(2.8+t)*4

Generally when first opponent catch the second opponent it is represented mathematically as

D_2=D_1

0.07t^2=(2.8+t)*4

0.07t^2=11.2+4t

0.07t^2-4t-11.2

t=59.817652833125294s \approx 59.8s

b)Generally the the total time traveled by the first opponent is mathematically given as

D_1=\frac{t^2}{4}

D_1=\frac{59.8^2}{4}

D_1=894.01m

3 0
3 years ago
Curtis, a student in our class, makes the following statement: The puck reached a slightly higher location on the ramp than I pr
Sindrei [870]

Answer and Explanation: No, the explanation is not plausible. The puck sliding on the ice is an example of the <u>Principle</u> <u>of</u> <u>Conservation</u> <u>of</u> <u>Energy</u>, which can be enunciated as "total energy of a system is constant. It can be changed or transferred but the total is always the same".

When a player hit the pluck, it starts to move, gaining kinetic energy (K). As it goes up a ramp, kinetic energy decreases and potential energy (P) increases until it reaches its maximum. When potential energy is maximum, kinetic energy is zero and vice-versa.

So, at the beginning of the movement the puck only has kinetic energy. At the end, it gains potential energy until its maximum.

The representation is as followed:

K_{i}+P_{i}=K_{f}+P_{f}

K_{i}+0=0+P_{f}

\frac{1}{2}mv^{2} = mgh

As we noticed, mass of the object can be cancelled from the equation, making height be:

h=\frac{v^{2}}{2g}

So, the height the puck reaches depends on velocity and acceleration due to gravity, not mass of the puck.

6 0
3 years ago
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