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True [87]
2 years ago
11

A man pushes a stalled car with a force of 100 N. If the acceleration of the car is 0.75 m/s 2 , what is the mass of the car?

Physics
1 answer:
shutvik [7]2 years ago
4 0
125 because f=ma so you would use 100=mx0.75
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A meter stick is pivoted at its 50 cm mark but does not balance because of non-uniformities in its material that cause its cente
Cerrena [4.2K]

Answer:

The mass of the stick is:

M=0,9428kg

The center of mass is at the 48,41cm mark

Explanation:

To be balanced in any case the resultant torque of the system must be zero.

For the first situation:

We have a 0,15kg mass al -0,4m from the pivot point, and a 0,3kg mass at +0,25m of the pivot point. On the other hand we know that the center of gravity of the stick is not at the 50cm mark point, so it will be at a X distance with a mass M, the torque sum:

0,15kg*(-0,4m)+0,3kg*0,25m+X*M=0

So:

(1)X*M=-0,015kgm

For the second situation:

Now the weights are interchanged, and as the pivot point has change, the distances from the pivot point are different:

We have a 0,3kg mass al -0,33m from the pivot point, and a 0,15kg mass at +0,32m of the pivot point. As the pivot has moved we have to move our reference for X: The center of gravity of the stick is at a X+0,07m distance with a mass M, the torque sum:

0,3kg*(-0,33m)+0,15kg*0,32m+(X+0,07m)*M=0

(X+0,07m)*M=0,051kgm

X*M+0,07m*M=0,051kgm

replacing X*M from (1):

-0,015kgm+0,07m*M=0,051kgm

The mass of the stick is:

M=(0,051kgm+0,015kgm)/0,07m=0,9428kg

and replacing this in (1):

X*0,9428kg=-0,015kgm

X=-0,015kgm/0,9428kg=-0,0159m=-1,59cm

As we took the 50cm mark as the reference, the center of mass is at the 48,41cm  mark

8 0
2 years ago
As in the video, we apply a charge +Q to the half-shell that carries the electroscope. This time, we also apply a charge –Q to t
Andreyy89

Answer:

Explanation:

When the positively charged half shell is brought in contact with the electroscope, its needle deflects due to charge present on the shell.

When the negatively charged half shell is brought in contact with the positively charged shell , the positive and negative charge present on each shell neutralises each other  .So both the shells lose their charges .The positive half shell also loses all its charges

When we separate the half shells , there will be no deflection  in the electroscope because both the shell have already lost their charges and they have become neutral bodies . So they will not be able to produce any deflection in the electroscope.

4 0
3 years ago
Read 2 more answers
A football player collides with another player. The force of the collision is
iragen [17]

Answer:

Impulse = 1000 Ns

Explanation:

Given the following data;

Force of collision = 1000 kg•m/s.

Time = 1 seconds

To find the impulse;

Mathematically, the impulse experienced by an object or body is given by the formula;

Impulse = force * time

Substituting into the formula, we have;

Impulse = 1000 * 1

Impulse = 1000 Ns

4 0
2 years ago
In the middle of a turn, you should _____________________. A. brake hard to maintain complete control over your vehicle B. accel
Elena L [17]

Answer:

D. Downshift to allow you to turn more sharply

3 0
3 years ago
A rocket fires two engines simultaneously. One produces a thrust of 725Ndirectly forward while the other gives a 513N thrust at
faust18 [17]

The magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.

<h3>What is the resultant force the two engines exert on the rocket?</h3>

The resultant force on the rocket is calculated thus:

The 513N thrust is resolved into vertical and horizontal components;

Horizontal component: 513N cos(32.4°) = 433.14 N

Vertical component: 513N sin(32.4°) = 274.88 N

Total forward force on the rocket = 725 N + 433.14 N = 1,158.14 N

Total force at right angles:

0 + 274.88 N = 274.88 N

The resultant force (F) is then given as follows:

F² = a² + b²

F² = (1158.14 N)² + (274.88 N)²

F = √1,416,847.27

F = 1,190.3

To find the direction:

tan X 274.88 N / 1,158.14 N

X = tan⁻¹ 0.237346089419241

X = 13.35°

Therefore, the magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.

In conclusion, the resultant force is obtained by resolving the forces into vertical and horizontal components.

Learn more about resultant force at: brainly.com/question/17434363

#SPJ1

8 0
1 year ago
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