Answer:
715 N
Explanation:
Since the system is moving at a constant velocity, the net force must be 0. The tension on the road is equal and opposite direction with the kinetic friction force created by the road and the stuntman.
Let g = 9.8 m/s2
Gravity and equalized normal force is:
N = P = mg = 107*9.8 = 1048.6 N
Kinetic friction force and equalized tension force on the rope is
Answer:
<u><em>a. True</em></u>
Explanation:
<em>Vectors are an important part of the language of science, mathematics, and engineering.</em>
Answer:
Explanation:
one end of tank will be circular in shape . Area of circle A
= π r² , r is radius of the circle
= 3.14 x 3²
A = 28.26 ft³
To calculate force on the circular area , we first find pressure at the center of the circle which is at depth equal to r
pressure at the center = h d g ' here h = depth = r , d = density of milk
pressure = 3 x 64.6 x 32 poundal / ft²
= 6201.6 poundal / ft²
total force on circular face = pressure at the center x area of circle
= 6201.6 x 28.26
= 175257.21 poundal .