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3 years ago

1. This image shows the various forces acting on a block of rock situated on a rock slope. What does arrow 4 represent?

Physics

2 answers:

Gelneren [198K]3 years ago

8 0

Answer:

B. Gravitational force

Explanation:

The gravitational force of an object (also called weight) is given by

$F=mg$

where m is the mass of the object and g is the acceleration of gravity, and it always points in the downward direction.

In this problem, the arrow labelled with 4 is the only force pointing downward: therefore, it must be the gravitational force.

The other arrows represent:

1 --> component of the gravitational force parallel to the plane

2 --> force of friction

3 --> component of the gravitational force perpendicular to the plane

Murrr4er [49]3 years ago

5 0

Answer:

Gravitational force

Explanation:

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Antimony consists of two major isotopes with the following atomic masses: 121Sb (120.904 amu) and 123Sb (122.904 amu). The avera

Bad White [126]

Answer:

121Sb=57.2%

123Sb=42.8%

Explanation:

We are given that

Atomic mass of 121Sb=120.904 amu

Atomic mass of 123Sb=122.904 amu

Average atomic mass of antimony=121.760 amu

We have to find the percent of each of the isotope.

Let x be the percent of 121Sb and 1-x be the percent of 123Sb.

Using formula of average atomic weight

Average atomic weight=atomic weight of 121Sb $\times$ percentage abundance of isotope 121Sb+atomic weight of 123Sb $\times$ percentage abundance of isotope 123Sb

Substitute the values

$121.760=120.904x+122.904(1-x)$

$121.760=120.904x+122.904-122.904x$

$121.760=-2x+122.904$

$2x=122.904-121.760$

$2x=1.144$

$x=\frac{1.144}{2}=0.572$

Percentage of 121Sb= $0.572\times 100=$ 57.2%

Abundance of isotope 123Sb=1-0.572=0.428

Percentage of isotope 123Sb= $0.428\times 100=$ 42.8%

7 0

4 years ago

Suppose that the clay balls model the growth of a planetesimal at various stages during its accretion. Choose the planetesimal t

motikmotik

Answer:2

Explanation:

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4 years ago

Three crates with various contents are pulled by a force F pull = 3615 N across a horizontal, frictionless roller‑conveyor syste

Dmitry_Shevchenko [17]

Answer:

m1=914.9kg

m2=604.9kg

m3=864.75kg

Explanation

I think we are suppose to find the mass of the crate.

The effective force that moves the body in positive x direction is 3615N

ΣFx = Σma

Then Fx=3615N

Then the masses be m1, m2 and m3

Then,

ΣF = Σ(ma)

3615=(m1+m2+m3)a

Given that a=1.516

The masses are

m1+m2+m3=, 2384.56. Equation 1

Between mass 1 and mass 2 is, F12=1387.

The effective force that pull mass 1 is 1387.

F12=m1 ×a

Therefore,

m1=F12/a

m1=1387/1.516

m1=914.9kg.

The effective force that pulls crate 1 and crate 2 is F23

F23=(m1+m2)a

Therefore

2304=(m1+m2)a

Therefore, since a=1.516

m1+m2=2304/1.516

m1+m2=1519.8kg

Since m1=914.9kg

So, m2=1519.8-m1

m2=1519.8-914.9

m2=604.9kg

Also from equation 1

m1+m2+m3=2384.56

Since m1=914.9kg and m2=604.9kg

Then, m3=2384.56-604.9-914.9

m3=864.75kg

3 0

3 years ago

What is the function of the cardiovascular system?

Lena [83]

The main function of the cardiovascular system is therefore to maintain blood flow to all parts of the body, to allow it to survive. Veins deliver used blood from the body back to the heart.

7 0

3 years ago

Read 2 more answers

What could this be???

yan [13]

In the same direction as the force

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3 years ago